Answer
Verified
498k+ views
Hint: In this question first use the property that the perimeter of the triangle is the sum of all the sides, later on apply the concept of Pythagoras Theorem, so use these concepts to reach the solution of the question.
Complete step-by-step answer:
Let the right angled triangle be ABC as shown in figure which is right angled at B.
And it is given that the hypotenuse of the triangle is 13 cm.
$ \Rightarrow AC = 13{\text{ cm}}$.
Let the other two sides of the triangle be x and y respectively.
$ \Rightarrow AB = x{\text{ cm, }}BC = y{\text{ cm}}$.
Now, it is given that the perimeter of a right angled triangle is 30 cm.
So as we know that the perimeter of a triangle is the sum of all sides.
$
\Rightarrow AB + BC + CA = 30 \\
\Rightarrow x + y + 13 = 30 \\
\Rightarrow x + y = 30 - 13 = 17 \\
\Rightarrow x + y = 17{\text{ cm}}.............\left( 1 \right) \\
$
Now as triangle ABC is a right angled triangle so, apply Pythagoras Theorem, we have
${\left( {{\text{Hypotenuse}}} \right)^2} = {\left( {{\text{Perpendicular}}} \right)^2} + {\left( {{\text{base}}} \right)^2}$
${\left( {AC} \right)^2} = {\left( {AB} \right)^2} + {\left( {BC} \right)^2}$
$
\Rightarrow {13^2} = {x^2} + {y^2} \\
\Rightarrow {x^2} + {y^2} = 169...........\left( 2 \right) \\
$
Now as we know that ${\left( {x + y} \right)^2} = {x^2} + {y^2} + 2xy$
Therefore from equation (1) and (2)
$
\Rightarrow {17^2} = 169 + 2xy \\
\Rightarrow 2xy = 289 - 169 \\
\Rightarrow 2xy = 120 \\
\Rightarrow xy = 60..........\left( 3 \right) \\
$
Now it is a known fact that ${\left( {x - y} \right)^2} = {\left( {x + y} \right)^2} - 4xy$
Therefore from equation (1) and (3).
$
\Rightarrow {\left( {x - y} \right)^2} = {\left( {17} \right)^2} - 4 \times 60 \\
\Rightarrow {\left( {x - y} \right)^2} = 289 - 240 = 49 \\
\Rightarrow x - y = \sqrt {49} = 7.........\left( 4 \right) \\
$
Now add equation (1) and (4)
$
\Rightarrow x + y + x - y = 17 + 7 \\
\Rightarrow 2x = 24 \\
$
$ \Rightarrow x = 12$ cm.
Now from equation (1)
$
x + y = 17 \\
\Rightarrow 12 + y = 17 \\
\Rightarrow y = 17 - 12 = 5 \\
$
$\therefore y = 5$ cm.
So, the length of the other two sides are 12 and 5 cm.
So, this is the required answer.
Note: Whenever we face such types of questions always remember that the perimeter of any figure is sum of all the sides, so use this property and construct the equation, later on apply the property of Pythagoras theorem and construct another equation then solve these two equations as above we will get the required length of the other sides of the triangle.
Complete step-by-step answer:
Let the right angled triangle be ABC as shown in figure which is right angled at B.
And it is given that the hypotenuse of the triangle is 13 cm.
$ \Rightarrow AC = 13{\text{ cm}}$.
Let the other two sides of the triangle be x and y respectively.
$ \Rightarrow AB = x{\text{ cm, }}BC = y{\text{ cm}}$.
Now, it is given that the perimeter of a right angled triangle is 30 cm.
So as we know that the perimeter of a triangle is the sum of all sides.
$
\Rightarrow AB + BC + CA = 30 \\
\Rightarrow x + y + 13 = 30 \\
\Rightarrow x + y = 30 - 13 = 17 \\
\Rightarrow x + y = 17{\text{ cm}}.............\left( 1 \right) \\
$
Now as triangle ABC is a right angled triangle so, apply Pythagoras Theorem, we have
${\left( {{\text{Hypotenuse}}} \right)^2} = {\left( {{\text{Perpendicular}}} \right)^2} + {\left( {{\text{base}}} \right)^2}$
${\left( {AC} \right)^2} = {\left( {AB} \right)^2} + {\left( {BC} \right)^2}$
$
\Rightarrow {13^2} = {x^2} + {y^2} \\
\Rightarrow {x^2} + {y^2} = 169...........\left( 2 \right) \\
$
Now as we know that ${\left( {x + y} \right)^2} = {x^2} + {y^2} + 2xy$
Therefore from equation (1) and (2)
$
\Rightarrow {17^2} = 169 + 2xy \\
\Rightarrow 2xy = 289 - 169 \\
\Rightarrow 2xy = 120 \\
\Rightarrow xy = 60..........\left( 3 \right) \\
$
Now it is a known fact that ${\left( {x - y} \right)^2} = {\left( {x + y} \right)^2} - 4xy$
Therefore from equation (1) and (3).
$
\Rightarrow {\left( {x - y} \right)^2} = {\left( {17} \right)^2} - 4 \times 60 \\
\Rightarrow {\left( {x - y} \right)^2} = 289 - 240 = 49 \\
\Rightarrow x - y = \sqrt {49} = 7.........\left( 4 \right) \\
$
Now add equation (1) and (4)
$
\Rightarrow x + y + x - y = 17 + 7 \\
\Rightarrow 2x = 24 \\
$
$ \Rightarrow x = 12$ cm.
Now from equation (1)
$
x + y = 17 \\
\Rightarrow 12 + y = 17 \\
\Rightarrow y = 17 - 12 = 5 \\
$
$\therefore y = 5$ cm.
So, the length of the other two sides are 12 and 5 cm.
So, this is the required answer.
Note: Whenever we face such types of questions always remember that the perimeter of any figure is sum of all the sides, so use this property and construct the equation, later on apply the property of Pythagoras theorem and construct another equation then solve these two equations as above we will get the required length of the other sides of the triangle.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
If the coordinates of the points A B and C be 443 23 class 10 maths JEE_Main
If the mean of the set of numbers x1x2xn is bar x then class 10 maths JEE_Main
What is the meaning of celestial class 10 social science CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Who was the leader of the Bolshevik Party A Leon Trotsky class 9 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Which is the largest saltwater lake in India A Chilika class 8 social science CBSE
Ghatikas during the period of Satavahanas were aHospitals class 6 social science CBSE