The resistivity of the material of potentiometer wire is \[5 \times {10^{ - 6}}\Omega m\;\]and its area of cross-section is\[5 \times {10^{ - 6}}{m^2}\]. If \[0.2\;A\;\] current is flowing through the wire, then the potential drop per metre length of the wire is
A. $0.1V{m^{ - 1}}$
B. $0.5V{m^{ - 1}}$
C. $0.25V{m^{ - 1}}$
D. $0.2V{m^{ - 1}}$
E. $0.001V{m^{ - 1}}$
Answer
Verified
463.5k+ views
Hint: We use the relation between resistance and resistivity to find the resistance of the material. Then we use the ohm's law to find the voltage. Dividing the voltage with the length of wire, voltage drop per meter length of wire can be found.
Formula used:
$\rho = \dfrac{{RA}}{l}$
Ohm's law:$V = iR$
Here,
Resistance is represented by $R$
Resistivity is represented by $\rho $
Length of wire is represented by $l$
Area of cross-section is represented by $A$
Voltage is represented by $V$
Current is represented by $i$
Complete step by step answer:
Resistivity is the electrical resistance of a material of unit area of unit length. Resistivity is a constant value for a given material.
Resistivity is equal to
$\rho = \dfrac{{RA}}{l}$
From which we can find resistance
$R = \dfrac{{\rho l}}{A}$
Given, length of the potentiometer, $l=1m$, $\rho = 5 \times {10^{ - 6}}\Omega m$ and $A = 5 \times {10^{ - 6}}{m^2}$. Putting these values in the formula, we find the resistance.
$R = \dfrac{{5 \times {{10}^{ - 6}} \times 1}}{{5 \times {{10}^{ - 6}}}}$
Given, $i=0.2A$
From ohm's law
$ V = iR $
$\implies V = \dfrac{{0.2 \times 5 \times {{10}^{ - 6}} \times 1}}{{5 \times {{10}^{ - 6}}}} $
$\implies V = 0.2V $
To find the voltage drop per meter we simply divide the voltage by the length
$V = \dfrac{{0.2}}{1}V{m^{ - 1}} = 0.2V{m^{ - 1}}$
Hence the voltage drop per meter of wire is $0.2V{m^{ - 1}}$.
So, the correct answer is “Option D”.
Note:
The potential drop for one meter or material is also called the potential gradient. It is the potential difference between two points on the wire that are one meter apart. Hence by dividing voltage by the length of wire we find the potential gradient. The units are volts per meter.
Resistivity depends on the type of material. The resistivity of two wires of the same material is always constant. Resistivity does not depend on the mass or length of the substance; it is a fixed value for different materials (like specific heat capacity) hence it is an intrinsic property. It purely depends on the nature of the element.
Formula used:
$\rho = \dfrac{{RA}}{l}$
Ohm's law:$V = iR$
Here,
Resistance is represented by $R$
Resistivity is represented by $\rho $
Length of wire is represented by $l$
Area of cross-section is represented by $A$
Voltage is represented by $V$
Current is represented by $i$
Complete step by step answer:
Resistivity is the electrical resistance of a material of unit area of unit length. Resistivity is a constant value for a given material.
Resistivity is equal to
$\rho = \dfrac{{RA}}{l}$
From which we can find resistance
$R = \dfrac{{\rho l}}{A}$
Given, length of the potentiometer, $l=1m$, $\rho = 5 \times {10^{ - 6}}\Omega m$ and $A = 5 \times {10^{ - 6}}{m^2}$. Putting these values in the formula, we find the resistance.
$R = \dfrac{{5 \times {{10}^{ - 6}} \times 1}}{{5 \times {{10}^{ - 6}}}}$
Given, $i=0.2A$
From ohm's law
$ V = iR $
$\implies V = \dfrac{{0.2 \times 5 \times {{10}^{ - 6}} \times 1}}{{5 \times {{10}^{ - 6}}}} $
$\implies V = 0.2V $
To find the voltage drop per meter we simply divide the voltage by the length
$V = \dfrac{{0.2}}{1}V{m^{ - 1}} = 0.2V{m^{ - 1}}$
Hence the voltage drop per meter of wire is $0.2V{m^{ - 1}}$.
So, the correct answer is “Option D”.
Note:
The potential drop for one meter or material is also called the potential gradient. It is the potential difference between two points on the wire that are one meter apart. Hence by dividing voltage by the length of wire we find the potential gradient. The units are volts per meter.
Resistivity depends on the type of material. The resistivity of two wires of the same material is always constant. Resistivity does not depend on the mass or length of the substance; it is a fixed value for different materials (like specific heat capacity) hence it is an intrinsic property. It purely depends on the nature of the element.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success
Master Class 12 Maths: Engaging Questions & Answers for Success
Master Class 12 Biology: Engaging Questions & Answers for Success
Master Class 12 Physics: Engaging Questions & Answers for Success
Master Class 12 Business Studies: Engaging Questions & Answers for Success
Master Class 12 English: Engaging Questions & Answers for Success
Trending doubts
Which are the Top 10 Largest Countries of the World?
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Draw a labelled sketch of the human eye class 12 physics CBSE
What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?
What is a transformer Explain the principle construction class 12 physics CBSE
What are the major means of transport Explain each class 12 social science CBSE