![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
The structure of a disaccharide formed by glucose and fructose is given below. Identify anomeric carbon atoms in monosaccharide units.
![](https://www.vedantu.com/question-sets/bf5a137b-345c-46a9-b4c6-cd2aaf3d9ac85103495384949094544.png)
(A) ‘a’ carbon of glucose and ‘a’ carbon of fructose
(B) ‘a’ carbon of glucose and ‘e’ carbon of fructose
(C) ‘a’ carbon of glucose and ‘b’ carbon of fructose
(D) ‘f’ carbon of glucose and ‘f’ carbon of fructose
Answer
123k+ views
Hint: The carbon derived the carbonyl carbon compound (maybe a ketone or aldehyde functional group) of the open-chain form of the carbohydrate molecule is known as an anomeric carbon.
Complete step by step answer:
-The cyclic monosaccharides or glycosides that are epimers, differing from each other in the configuration of ${{C}_{1}}$ carbon if they are aldoses or in the configuration at ${{C}_{2}}$carbon if they are ketoses are known as anomers.
-An epimer at the hemiacetal or hemiketal carbon in a cyclic sugar is an anomer, and the atom is called anomeric carbon.
-The process of conversion of one anomer to another anomer is known as anomerization.
-According to the configurational relationship between the anomic centre and the anomeric reference atom between the two anomers, they are denoted as alpha or beta anomers.
-If the exocyclic oxygen atom in the cyclic Fischer projection at the anomeric centre is cis to the exocyclic oxygen attached to the anomeric reference atom (in the OH group), then the anomer is referred as alpha $(\alpha )$ anomer.
- If the exocyclic oxygen atom in the cyclic Fischer projection at the anomeric centre is trans to the exocyclic oxygen attached to the anomeric reference atom (in the OH group), the anomeric is referred as beta $(\beta )$ anomer.
-In this molecule, the ‘a’ carbon atom of glucose and ‘b’ carbon atom of the fructose molecule is adjacent to oxygen atoms in the cyclic structures, hence they are anomeric carbons.
![](https://www.vedantu.com/question-sets/0c56debd-7d6d-432c-ae8d-f765ce2e7dcd4184870692578812434.png)
So, the correct answer is option C.
Note: Two different anomers will differ from each other in their physical properties, melting points as well as in specific rotations. Since anomers show the difference in their physical properties and thus have different stabilizing and destabilizing effects from each other. The anomer that has an electron-withdrawing group (typically oxygen or a nitrogen atom) in axial orientation on the ring is said to exhibit an anomeric effect. Hydrogen bonds if present between the anomeric groups or on the other groups within the ring leads to the stabilization of the anomer. Dipolar repulsions between the anomeric group or in the other groups present on the ring cause the destabilization of the anomer.
Complete step by step answer:
-The cyclic monosaccharides or glycosides that are epimers, differing from each other in the configuration of ${{C}_{1}}$ carbon if they are aldoses or in the configuration at ${{C}_{2}}$carbon if they are ketoses are known as anomers.
-An epimer at the hemiacetal or hemiketal carbon in a cyclic sugar is an anomer, and the atom is called anomeric carbon.
-The process of conversion of one anomer to another anomer is known as anomerization.
-According to the configurational relationship between the anomic centre and the anomeric reference atom between the two anomers, they are denoted as alpha or beta anomers.
-If the exocyclic oxygen atom in the cyclic Fischer projection at the anomeric centre is cis to the exocyclic oxygen attached to the anomeric reference atom (in the OH group), then the anomer is referred as alpha $(\alpha )$ anomer.
- If the exocyclic oxygen atom in the cyclic Fischer projection at the anomeric centre is trans to the exocyclic oxygen attached to the anomeric reference atom (in the OH group), the anomeric is referred as beta $(\beta )$ anomer.
-In this molecule, the ‘a’ carbon atom of glucose and ‘b’ carbon atom of the fructose molecule is adjacent to oxygen atoms in the cyclic structures, hence they are anomeric carbons.
![](https://www.vedantu.com/question-sets/0c56debd-7d6d-432c-ae8d-f765ce2e7dcd4184870692578812434.png)
So, the correct answer is option C.
Note: Two different anomers will differ from each other in their physical properties, melting points as well as in specific rotations. Since anomers show the difference in their physical properties and thus have different stabilizing and destabilizing effects from each other. The anomer that has an electron-withdrawing group (typically oxygen or a nitrogen atom) in axial orientation on the ring is said to exhibit an anomeric effect. Hydrogen bonds if present between the anomeric groups or on the other groups within the ring leads to the stabilization of the anomer. Dipolar repulsions between the anomeric group or in the other groups present on the ring cause the destabilization of the anomer.
Recently Updated Pages
JEE Main 2025 - Session 2 Registration Open | Exam Dates, Answer Key, PDF
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How to find Oxidation Number - Important Concepts for JEE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
How Electromagnetic Waves are Formed - Important Concepts for JEE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electrical Resistance - Important Concepts and Tips for JEE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Average Atomic Mass - Important Concepts and Tips for JEE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Chemical Equation - Important Concepts and Tips for JEE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
JEE Main Login 2045: Step-by-Step Instructions and Details
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Chemistry Online Mock Test for Class 12
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Physics Average Value and RMS Value JEE Main 2025
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2023 January 25 Shift 1 Question Paper with Answer Keys & Solutions
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main 2022 June 29 Shift 2 Question Paper with Answer Keys & Solutions
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Biomolecules Class 12 Notes: CBSE Chemistry Chapter 10
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
NCERT Solutions for Class 12 Chemistry In Hindi Chapter 3 Electrochemistry Hindi Medium
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Main Course 2025: Get All the Relevant Details
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Coordination Compounds Class 12 Notes: CBSE Chemistry Chapter 5
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
JEE Advanced 2025 Revision Notes for Practical Organic Chemistry
![arrow-right](/cdn/images/seo-templates/arrow-right.png)