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Three unbiased coins are tossed together. Find the probability of getting: One head
Answer
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Hint: Here we need to find the probability of getting one head when three coins are tossed together by using the concept of probability.
Complete step-by-step answer:
You have been given 3 coins and the event is a random experiment of tossing three coins.
So you will get
Sample Space = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
Therefore S(n) =8.
Now we need to find the events of getting one head, when three coins are tossed together that is
{HTT, THT, TTH}.
Favorable outcomes are 3.
Probability = $\dfrac {\text{No. of favourable outcomes}}{\text{Total no. of outcomes}}$
Therefore, Required Probability $ = \dfrac{3}{8}$.
Note: In these types of questions you must first list down the sample space and the favorable outcomes and then find the probability. Concept of combinations can also be used.
Complete step-by-step answer:
You have been given 3 coins and the event is a random experiment of tossing three coins.
So you will get
Sample Space = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}
Therefore S(n) =8.
Now we need to find the events of getting one head, when three coins are tossed together that is
{HTT, THT, TTH}.
Favorable outcomes are 3.
Probability = $\dfrac {\text{No. of favourable outcomes}}{\text{Total no. of outcomes}}$
Therefore, Required Probability $ = \dfrac{3}{8}$.
Note: In these types of questions you must first list down the sample space and the favorable outcomes and then find the probability. Concept of combinations can also be used.
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