Answer
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Hint: When the two polaroid is kept across to each other one of them have rotated angle of $60{}^\circ $, So, we have the intensity of polarized light as ${{I}_{0}}$ so the intensity of the first polaroid is $\dfrac{{{I}_{0}}}{2}$. Using the given information the equation. $I={{I}_{0}}{{\cos }^{2}}\theta $. Which can be written as ${{I}_{0}}=\dfrac{{{I}_{0}}}{2}{{\cos }^{2}}\theta $ and it used for finding the answer.
Complete step by step solution:When the two polaroid are kept crossed to each other. If one of them is rotated at an angle of \[60{}^\circ \]
Let,
The intensity of un polarized light be ${{I}_{0}},$ So, the intensity of the first polaroid is $\dfrac{{{I}_{0}}}{2}$
On rotating through $60{}^\circ .$ The intensity of light from sound polaroid.
As we have, $I={{I}_{0}}{{\cos }^{2}}\theta $
$\therefore I=\left( \dfrac{{{I}_{0}}}{2} \right){{\left( \cos 60{}^\circ \right)}^{2}}$
$=\dfrac{{{I}_{0}}}{2}\times \dfrac{1}{4}$
$=\dfrac{{{I}_{0}}}{8}$
$\therefore I=0.125{{I}_{0}}$
Therefore,
Percentage of incident light transmitted through the system $=0.125\times 100=12.5%$
Hence,
The required percentage is $12.5%$
Additional Information:
Polarization is a property that is applying to the transverse waves which specifies that orientation of oscillations. The direction of oscillation is perpendicular in a transverse wave. For an example for a polarized transverse wave that is vibration traveling along the string. (or a guitar string). The vibrations can be in horizontal or vertical direction. Depends upon how string is Plock. Some of the optical measurement steps are based on polarization. Polarization is crucial or it must be taken into account and it is controlled. Such examples are numbers for mention.
Note:
First of all understand the part of the question that is asked. Read the question carefully and solve that first in which it is difficult for you to solve. As you are reading the answer try to give the answer before you see any options. If you are expert in writing lengthy answers such as short answers. This strategy will be a great help for us. In the option try to eliminate the wrong option. Also underline the key part of the question. Don’t read the question too much. These are the points you have to remember while solving any question.
Complete step by step solution:When the two polaroid are kept crossed to each other. If one of them is rotated at an angle of \[60{}^\circ \]
Let,
The intensity of un polarized light be ${{I}_{0}},$ So, the intensity of the first polaroid is $\dfrac{{{I}_{0}}}{2}$
On rotating through $60{}^\circ .$ The intensity of light from sound polaroid.
As we have, $I={{I}_{0}}{{\cos }^{2}}\theta $
$\therefore I=\left( \dfrac{{{I}_{0}}}{2} \right){{\left( \cos 60{}^\circ \right)}^{2}}$
$=\dfrac{{{I}_{0}}}{2}\times \dfrac{1}{4}$
$=\dfrac{{{I}_{0}}}{8}$
$\therefore I=0.125{{I}_{0}}$
Therefore,
Percentage of incident light transmitted through the system $=0.125\times 100=12.5%$
Hence,
The required percentage is $12.5%$
Additional Information:
Polarization is a property that is applying to the transverse waves which specifies that orientation of oscillations. The direction of oscillation is perpendicular in a transverse wave. For an example for a polarized transverse wave that is vibration traveling along the string. (or a guitar string). The vibrations can be in horizontal or vertical direction. Depends upon how string is Plock. Some of the optical measurement steps are based on polarization. Polarization is crucial or it must be taken into account and it is controlled. Such examples are numbers for mention.
Note:
First of all understand the part of the question that is asked. Read the question carefully and solve that first in which it is difficult for you to solve. As you are reading the answer try to give the answer before you see any options. If you are expert in writing lengthy answers such as short answers. This strategy will be a great help for us. In the option try to eliminate the wrong option. Also underline the key part of the question. Don’t read the question too much. These are the points you have to remember while solving any question.
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