![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
Which among the following is a polar molecule?
\[
A.{\text{ }}B{H_3} \\
B.{\text{ }}N{F_3} \\
C.{\text{ }}{C_2}{H_6} \\
D.{\text{ }}S{F_6} \\
E.{\text{ }}CC{l_4} \\
\]
Answer
489.3k+ views
Hint: In order to solve the given problem and find the polar molecule amongst the given options we will first understand the concept of polarity of molecules and also understand the concept behind the classification of a molecule as polar or nonpolar on the basis of their dipole moment.
Complete step by step solution:
Polarity is a division of the electric charge which leads to a molecule or its chemical groups having an electric dipole moment with a negative charged end and a positively charged end. Regardless of a difference in electronegativity between the bound atoms, polar molecules may have polar bonds.
Polarity of any given molecule is found on the basis of the dipole moment of the molecule which is found out by the visualisation of positive and negative charge of the molecule.
On the basis of structure of the molecule the molecules are of two types:- symmetrical and unsymmetrical molecules.
The dipole moment of symmetrical molecule is zero as the net charge of in the molecule is cancelled out so these molecules does not has polarity
The bond dipole moment uses the concept of the electric dipole moment to calculate a chemical bond's polarity within a molecule. It occurs whenever the positives and negative charges are separated.
But the dipole moment of a non symmetrical molecule is not zero as the charge does not cancel out each other so unsymmetrical molecules are generally polar.
Amongst the given options the structure of each of the molecules other than $N{F_3}$ is non symmetrical and so the dipole moment of all the other molecules is zero.
Structure of $N{F_3}$
As we can see in the diagram the structure of $N{F_3}$ is non symmetrical due to the presence of a lone pair. So the dipole moment of $N{F_3}$ is not zero so the molecule is polar.
Hence, $N{F_3}$ is a polar molecule.
So, the correct answer is option B.
Note: In order to solve such problems related to polarity of the molecule. Students must be aware of the concept of dipole moment and also should know the structure of the molecules. $N{F_3}$ or nitrogen trifluoride can be used in relatively few manufacturing processes. This is used mainly in the manufacture of semiconductors and LCD (Liquid Crystal Display) displays, and certain types of solar panels and chemical lasers.
Complete step by step solution:
Polarity is a division of the electric charge which leads to a molecule or its chemical groups having an electric dipole moment with a negative charged end and a positively charged end. Regardless of a difference in electronegativity between the bound atoms, polar molecules may have polar bonds.
Polarity of any given molecule is found on the basis of the dipole moment of the molecule which is found out by the visualisation of positive and negative charge of the molecule.
On the basis of structure of the molecule the molecules are of two types:- symmetrical and unsymmetrical molecules.
The dipole moment of symmetrical molecule is zero as the net charge of in the molecule is cancelled out so these molecules does not has polarity
The bond dipole moment uses the concept of the electric dipole moment to calculate a chemical bond's polarity within a molecule. It occurs whenever the positives and negative charges are separated.
But the dipole moment of a non symmetrical molecule is not zero as the charge does not cancel out each other so unsymmetrical molecules are generally polar.
Amongst the given options the structure of each of the molecules other than $N{F_3}$ is non symmetrical and so the dipole moment of all the other molecules is zero.
Structure of $N{F_3}$
![seo images](https://www.vedantu.com/question-sets/7a919583-2a38-4487-b32d-0005efe8de495444548918991658571.png)
As we can see in the diagram the structure of $N{F_3}$ is non symmetrical due to the presence of a lone pair. So the dipole moment of $N{F_3}$ is not zero so the molecule is polar.
Hence, $N{F_3}$ is a polar molecule.
So, the correct answer is option B.
Note: In order to solve such problems related to polarity of the molecule. Students must be aware of the concept of dipole moment and also should know the structure of the molecules. $N{F_3}$ or nitrogen trifluoride can be used in relatively few manufacturing processes. This is used mainly in the manufacture of semiconductors and LCD (Liquid Crystal Display) displays, and certain types of solar panels and chemical lasers.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Define least count of vernier callipers How do you class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The combining capacity of an element is known as i class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the image of the point 38 about the line x+3y class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Can anyone list 10 advantages and disadvantages of friction
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Distinguish between Mitosis and Meiosis class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)