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Hint: Rosenmund reaction involves the conversion of that compound which contains a halogen atom. The product formed after the reaction is the molecule which upon further reduction gives us alcohol.
Complete answer: To find out the correct option, we should know about what is Rosenmund reaction. So, first of all, let’s see this.
Rosenmund reaction is a hydrogenation reaction. Now the question arises what is hydrogenation. Hydrogenation is a process that involves the addition of hydrogen atoms across a double or triple bond. The Rosenmund reaction involves selectively reduction of acyl chloride to an aldehyde.
The Pd metal on $BaS{O_4}$ is called Rosenmund reagent.
In the above reaction what happens is that a molecule of an acyl chloride is reduced to a molecule of aldehyde in the presence of hydrogen gas over palladium metal surface poisoned by barium sulphate.
So, the correct answer is “Option D”.
Additional Information: Rosenmund catalyst can be prepared by the reduction of palladium(II) chloride solution in the presence of $BaS{O_4}$. The $BaS{O_4}$ has a low surface area which reduces the activity of palladium metal. This helps in prevention of over-reduction.
Note: We can prepare a large number of aldehydes by this method but formaldehyde can-not be prepared by this method because for the formation of formaldehyde; we require formyl chloride which will be reduced to formaldehyde. The formyl chloride is not stable at room temperature. So, this reaction is not possible.
Complete answer: To find out the correct option, we should know about what is Rosenmund reaction. So, first of all, let’s see this.
Rosenmund reaction is a hydrogenation reaction. Now the question arises what is hydrogenation. Hydrogenation is a process that involves the addition of hydrogen atoms across a double or triple bond. The Rosenmund reaction involves selectively reduction of acyl chloride to an aldehyde.
The Pd metal on $BaS{O_4}$ is called Rosenmund reagent.
In the above reaction what happens is that a molecule of an acyl chloride is reduced to a molecule of aldehyde in the presence of hydrogen gas over palladium metal surface poisoned by barium sulphate.
So, the correct answer is “Option D”.
Additional Information: Rosenmund catalyst can be prepared by the reduction of palladium(II) chloride solution in the presence of $BaS{O_4}$. The $BaS{O_4}$ has a low surface area which reduces the activity of palladium metal. This helps in prevention of over-reduction.
Note: We can prepare a large number of aldehydes by this method but formaldehyde can-not be prepared by this method because for the formation of formaldehyde; we require formyl chloride which will be reduced to formaldehyde. The formyl chloride is not stable at room temperature. So, this reaction is not possible.
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