Answer
Verified
367.5k+ views
Hint: The organic compound anisole, also known as methoxy benzene, has the formula. It's a colourless liquid with an anise seed aroma, and many of its derivatives can be used in natural and synthetic fragrances. The compound is mostly synthesised and serves as a precursor to other synthetic compounds.
Complete answer:
Methoxy benzene forms phenol and iodomethane as it reacts with hydroiodic acid HI.
We can represent this reaction as,
We know that methoxy benzene is alkyl aryl ether. So, methoxy benzene has two bonds that are joined by an oxygen atom. The oxygen-methyl group (O-alkyl bond) is one, and the oxygen-aryl group is the other (O-Aryl bond). Because of the partial double bond character of the Oxygen-Aryl bond, it is the most stable of the three.
That is, oxygen-methyl bond is cleaved in this reaction, resulting in methyl iodide and phenol.
The reaction between HI and methoxy benzene occurs in two stages and they are;
Stage 1: By trapping $H^+$ from HI, the oxygen in ether is protonated (added a proton), hence forming a protonated ether molecule known as oxonium ion.
Stage 2: Since Iodide ion (I-) is a strong nucleophile, the \[S{N_2}\] reaction occurs in this step. To form methyl iodide and phenol, the I- ion preferentially targets the protonated ether molecule's least substituted carbon (in this case, the methyl group).
Note:
We should also remember that phenol is an aromatic organic compound with the molecular formula. The chemical compound with the formula \[C{H_3}I\] is iodomethane, also known as methyl iodide and commonly abbreviated "MeI."
Complete answer:
Methoxy benzene forms phenol and iodomethane as it reacts with hydroiodic acid HI.
We can represent this reaction as,
We know that methoxy benzene is alkyl aryl ether. So, methoxy benzene has two bonds that are joined by an oxygen atom. The oxygen-methyl group (O-alkyl bond) is one, and the oxygen-aryl group is the other (O-Aryl bond). Because of the partial double bond character of the Oxygen-Aryl bond, it is the most stable of the three.
That is, oxygen-methyl bond is cleaved in this reaction, resulting in methyl iodide and phenol.
The reaction between HI and methoxy benzene occurs in two stages and they are;
Stage 1: By trapping $H^+$ from HI, the oxygen in ether is protonated (added a proton), hence forming a protonated ether molecule known as oxonium ion.
Stage 2: Since Iodide ion (I-) is a strong nucleophile, the \[S{N_2}\] reaction occurs in this step. To form methyl iodide and phenol, the I- ion preferentially targets the protonated ether molecule's least substituted carbon (in this case, the methyl group).
Note:
We should also remember that phenol is an aromatic organic compound with the molecular formula. The chemical compound with the formula \[C{H_3}I\] is iodomethane, also known as methyl iodide and commonly abbreviated "MeI."
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Trending doubts
Difference Between Plant Cell and Animal Cell
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
10 examples of evaporation in daily life with explanations
Write a letter to the principal requesting him to grant class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Name 10 Living and Non living things class 9 biology CBSE