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Electrochemistry Class 12 Notes CBSE Chemistry Chapter 2 (Free PDF Download)

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Electrochemistry Notes for CBSE Class 12 Chemistry Chapter 2 - Free PDF Download

Electrochemistry is a vital section of chemistry that determines the function of electrodes and reactors. Vedantu’s Electrochemistry notes class 12 tries to situate the ideas behind the chemical reactions. 


An electrochemical cell is a tool that produces the difference between forms of the electrode through a chemical reaction. There are ideally two types of electron conductors that get separated by an ionic conductor. An electron conductor further links it, making it accessible. 


Class 12 Electrochemistry Notes explain this function of electrons where two metallic electrodes are present. These metallic electrodes are immersed in an electrolytic solution for power generation. By thorough reading of Electrochemistry Class 12 Notes PDF Download, students will know that the ionic conductor is a vital part of cells.

Download CBSE Class 12 Chemistry Notes 2024-25 PDF

Also, check CBSE Class 12 Chemistry revision notes for other chapters:

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Electrochemistry Class 12 Notes Chemistry - Basic Subjective Questions

Section – A (1 Mark Questions)

1. The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called ___

Ans. The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called cell emf.

 

2. Greater the solvation of ions, ____ is the conductivity. (greater/lesser)

Ans. Conductivity depends upon solvation of ions present in solution. Greater the solvation of ions, lesser is the conductivity.


3. What is an inert electrode?

Ans. The inert electrode is an electrode that serves only as a source or sinks for electrons. It provides a surface for oxidation or reduction reaction but not for the redox reaction. It does not participate in the cell reaction.


4. Define the term specific resistance and give its SI unit.

Ans. The specific resistance of a substance is its resistance when cell is one meter long and its area of cross Section is one m2. Its SI unit is  Ωm (ohm meter)


5. What is meant by Faraday’s constant?

Ans.  Faraday’s constant is the quantity of charge carried by one mole of electrons.
1 F = 96500 C/mol


6. Conductivity of an electrolytic solution depends on _____ and _____.

Ans. Conductivity or specific conductance k (kappa). It depends on the nature of the electrolyte and concentration of the electrolyte.


7. What is Kohlrausch’s law?

Ans. Kohlrausch’s law states that the equivalent conductivity of an electrolyte at infinite dilution is equal to the sum of the conductances of the anions and cations.


8. Can absolute electrode potential of an electrode be measured?

Ans. No, only the difference in potential between two electrodes can be measured.


9. Can Ecell or ΔrG for cell reaction ever be equal to zero?

Ans. At equilibrium ΔrG  = 0 Ecell = 0


10. What are the units of cell constant?

Ans. cm-1 or m-1


Section – B (2 Marks Questions)

11. Depict (cell representation) the galvanic cell in which the cell reaction is Cu + 2Ag+ → 2Ag + Cu2+

Ans. Cu + 2Ag+ → 2Ag + Cu2+ cell can be represented is Cu | Cu2+ || Ag+ | Ag


12. A solution is placed in two different cells having cell constant 0.1 and 0.5 cm-1 respectively. Which of the two will have greater value of specific conductance?

Ans. Both will have same value of specific conductance.

13. Why is alternating current used for measuring resistance of an electrolytic solution?

Ans. Alternating current is used for measuring the resistance of an electrolytic solution because DC current can change the composition of the solution and the concentration will not remain constant.


14. Solutions of two electrolytes 'A' and 'B' are diluted. The Λm of 'B' increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer.

Ans. 'B' is strong electrolyte. For strong electrolyte Λm increases slowly with dilution since the number of ions remains the same, only the interionic attraction decreases thus the molar conductivity increases slightly.

15. When acidulated water (dil H2SO4 solution) is electrolysed, will the pH of the solution be affected? Justify your answer.

Ans. pH of the solution remains constant as [H+] remains same during the whole reaction.

At anode: 2H2O (l) →  O2 (g) +  4H+ + 4e

At cathode: 4H+ + 4e → 2H2(g)


16. Can Fe3+ oxidise Br to Br2 under standard conditions?

       $E^{\theta }_{Fe^{3+}/Fe^{2+}}=0.77W,\;E^{\theta }_{Br_{2}/Br^{-}}=1.09W$

Ans. No, because for the reaction, 

$Fe^{3+}+Br^{-}\rightarrow Fe^{2+}+\frac{1}{2}Br_{2}$     

$E^{\theta }=0.771=1.09=-0.319\;V$ is negative


17. A very thin copper plate is electro-plated with gold using gold chloride in HCl. The current was passed for 20 minutes and the increase in the weight of the plate was found to be 2 gram (Au = 197). The current passed was:

Ans. w = zit

$2=\frac{197}{3}\times\frac{i\times20\times60}{96500}$

i = 2.448 amp.


19. What is the reaction taking place at the anode when an aqueous solution of copper sulphate is electrolysed using Pt-electrodes (inert)?

Ans. At anode oxidation takes place, and oxidation is defined as loss of electrons. So the reaction should be

$2H_{2}O\rightarrow O_{2}+4H^{+}+4e^{-}$

Since mobility of OH is greater than $SO_{4}^{2-}$

$\therefore$ oxidation of $SO_{4}^{2-}$ will not occur.


20. The molar conductivities of $\Lambda_{\mathrm{NaOAc}}^{\circ}$ and $\Lambda_{\mathrm{HCl}}^{\circ}$ at infinite dilution in water at 25ºC are 91.0 and 426.2 S cm2/mol respectively. To calculate $\Lambda_{\mathrm{NaOAc}}^{\circ}$, the additional value required is

Ans. To calculate molar conductance of acetic acid at infinite dilution $\Lambda_{\mathrm{NaOAc}}^{\circ}$ , molar conductance of HCl at infinite dilution $\Lambda_{\mathrm{HCl}}^{\circ}$, Sodium Acetate $\Lambda_{\mathrm{NaOAc}}^{\circ}$ and Sodium chloride $\Lambda_{\mathrm{NaCl\circ}}$ should be known.

$\Lambda_{\mathrm{mHOAc}}^{\circ}=\Lambda_{\mathrm{mHCl}}^{\circ}+\Lambda_{\mathrm{mNaOAc}}^{\circ}-\Lambda_{\mathrm{mNaCl}}^{\circ}$

PDF Summary - Class 12 Chemistry Electrochemistry Notes (Chapter 2)


Electrochemistry

Electrochemistry is the study of generating electricity from the energy produced during a spontaneous chemical reaction, as well as the application of electrical energy to non-spontaneous chemical changes.


Electrochemical Cells

A spontaneous chemical reaction is one that can occur on its own, and in such a reaction, the system's Gibbs energy falls. This energy is then transformed into electrical energy. It is also feasible to force non-spontaneous processes to occur by providing external energy in the form of electrical energy. Electrochemical Cells are used to carry out these interconversions. 


Types

Two types of electrochemical cells are present: Galvanic cells, which converts chemical energy into electrical energy and electrolytic cells which converts electrical energy into chemical energy.


Galvanic Cells

A spontaneous chemical process or reaction is used to extract cell energy, which is then transformed to electric current.


For example, a Daniell Cell is a Galvanic Cell in which the redox reaction is carried out using Zinc and Copper.


$Zn(s) + C{u^{2 + }}(aq) \to Z{n^{2 + }}(aq) + Cu(s)$ 


Oxidation Half: $Zn(s) \to Z{n^{2 + }}(aq) + 2{e^ - }$ 


Reduction Half: $C{u^{2 + }}(aq) + 2{e^ - } \to Cu(s)$ 


The reducing agent is $Zn$ , and the oxidising agent is $C{u^{2 + }}$ .


Electrodes are another name for half cells. The anode is the oxidation half, and Cathode is the reduction half. Cathode is a term used to describe a type of electrode. In the external circuit, electrons pass from anode to cathode. Negative polarity is assigned to the anode. Positive polarity is assigned to the cathode. Daniell Cell is a fictional character created by Daniell Cell. The anode is $Zn$ , while the cathode is $Cu$ .

 

Electrolytic Cell

These electrodes are submerged in an electrolytic solution that contains both cations and anions. When current is supplied, the ions migrate towards electrodes of opposite polarity, where they undergo simultaneous reduction and oxidation.


Preferential Discharge of Ions

When more than one cation or anion is present, the discharge process becomes competitive. Any ion that needs to be discharged requires energy, and if there are multiple ions present, the ion that requires the most energy will be discharged first.


Electrode Potential

It can be defined as an element's tendency to lose or gain electrons when in contact with its own ions, causing it to become positively or negatively charged. Depending on whether oxidation or reduction has occurred, the electrode potential will be referred to as oxidation or reduction potential.


$M(s)\underset{{{\text{Reduction}}}}{\overset{{{\text{Oxidation}}}}{\longleftrightarrow}}{M^{n + }}(aq) + n{e^ - }$

 

${M^{n + }}(aq) + n{e^ - }\underset{{{\text{Oxidation}}}}{\overset{{{\text{Reduction}}}}{\longleftrightarrow}}M(s)$

 

Characteristics

  1. The magnitude and sign of the oxidation and reduction potentials are equal. 

  2. Because E is not a thermodynamic property, its values do not add up.


Standard Electrode Potential $({E^ \circ })$ 

It can be described as an electrode's electrode potential measured in comparison to a standard hydrogen electrode under standard conditions. The following are the standard conditions:

  1. A 1M concentration of each ion in the solution.

  2. A 298 K temperature.

  3. Each gas has a pressure of one bar.


Electrochemical Series

The half-cell potential values are standard and are represented as standard reduction potential values in the table at the conclusion, commonly known as the Electrochemical Series.


Cell Potential or EMF of a Cell

Cell potential is the difference between the electrode potentials of two half cells. If no current is pulled from the cell, it is known as electromotive force (EMF). 


${E_{cell}} = {E_{cathode}} + {E_{anode}}$ 


For this equation we take oxidation potential of anode and reduction potential of cathode. 


Since anode is put on left and cathode on right, it follows therefore:


$ = {E_R} + {E_L}$ 


For a Daniel Cell, therefore:


$E_{cell}^ \circ  = E_{C{u^{2 + }}/Cu}^ \circ  - E_{Zn/Z{n^{2 + }}}^ \circ  = 0.34 + (0.76) = 1.10\;V$ 


Cell Diagram or Representation of a Cell

In accordance with IUPAC recommendations, the following conventions or notations are used to write the cell diagram. The Daniel cell has the following representation:


$Zn(s)|Z{n^{2 + }}({C_1})||C{u^{2 + }}({C_2})|Cu(s)$ 


  1. The anode half cell is written on the left, while the cathode half cell is written on the right. 

  2. The metal is separated from an aqueous solution of its own ions by a single vertical line.

Anodic Chamber: $Zn(s)|Z{n^{2 + }}(aq)$ 

Cathodic Chamber: $C{u^{2 + }}(aq)|Cu(s)$ 

  1. A salt bridge is represented by a double vertical line.

  2. After the formula of the corresponding ion, the molar concentration (C) is placed in brackets.

  3. The cell's e.m.f. value is written on the cell's extreme right side. As an example:

$Zn(s)|Z{n^{2 + }}(1M)||C{u^{2 + }}(1M)|Cu$ , EMF = +1.1 V

  1. If an inert electrode, such as platinum, is used in the cell's construction, it may be written in brackets alongside the working electrode, as when a zinc anode is coupled to a hydrogen electrode. 

$Zn(s)|Z{n^{2 + }}({C_1})||{H^ + }({C_2})|{H_2}(Pt)(s)$ 


Salt Bridge

The salt bridge maintains charge balance and completes the circuit by allowing ions to flow freely through it. It contains a gel containing an inert electrolyte such as $N{a_2}S{O_4}$  or $KN{O_3}$ . Through the salt bridge, negative ions travel to the anode and positive ions flow to the cathode, maintaining charge balance and allowing the cell to function.


Salt Bridge


Spontaneity of a Reaction

$\Delta G =  - nF{E_{cell}}$ 


$\Delta G$ should be negative and cell potential should be positive for a spontaneous cell reaction.


In the following equation, if we take the standard value of cell potential, we will also get the standard value of $\Delta G$ .


$\Delta {G^ \circ } =  - nFE_{CELL}^ \circ $ 


Types of Electrodes

Metal – Metal Ion Electrodes

An electrolyte solution containing metal ions is dipped into a metal rod/plate. Because of the potential difference between these two phases, this electrode can function as both a cathode and an anode.


Anode: $M \to {M^{n + }} + n{e^ - }$ 


Cathode: ${M^{n + }} + n{e^ - } \to M$ 


Gas Electrodes

Electrode gases such as ${H_2}$  and $C{l_2}$  are used in conjunction with their respective ions. ${H_2}$  gas, for example, is utilised in conjunction with a dilute solution of $HCl$  (${H^ + }$  ions). To avoid reacting with the acid, the metal should be inert. 


Gas Electrodes


Anode: ${H_2} \to 2{H^ + } + 2{e^ - }$

 

Cathode: $2{H^ + } + 2{e^ - } \to {H_2}$ 


The hydrogen electrode is also used as a standard for measuring the potentials of other electrodes. As a reference, its own potential is set at $0\;V$ . The concentration of the HCl used as a reference is 1 M, and the electrode is known as the "Standard Hydrogen Electrode (SHE)".


Metal – Insoluble Salt Electrode

As electrodes, we use salts of several metals that are only sparingly soluble with the metal itself. When we employ $AgCl$  with $Ag$ , for example, there is a potential gap between these two phases, as seen in the following reaction:


$AgCl(s) + {e^ - } \to Ag(s) + C{l^ - }$ 


This electrode is made by dipping a silver rod in a solution containing $AgCl(s)$  and $C{l^ - }$  ions.


Calomel Electrode

Mercury is combined with two other phases: calomel paste $(H{g_2}C{l_2})$  and a $C{l^ - }$ ions containing electrolyte.


Calomel Electrode


Cathode: $H{g_2}C{l_2}(s) + 2{e^ - } \to 2Hg(l) + 2C{l^ - }(aq)$ 


Anode: $2Hg(l) + 2C{l^ - }(aq) \to H{g_2}C{l_2}(s) + 2{e^ - }$ 


This electrode is also utilised as a reference point for determining other potentials. It's also known as Standard Calomel Electrode in its standard form (SCE).


Redox Electrode

Two distinct oxidation states of the same metal are used in the same half cell in these electrodes. For example, $F{e^{2 + }}$  and $F{e^{3 + }}$  are dissolved in the same container and the electron transfer is performed using a platinum inert electrode.


The following reactions may occur:


Anode: $F{e^{2 + }} \to F{e^{3 + }} + {e^ - }$

 

Cathode: $F{e^{3 + }} + {e^ - } \to F{e^{2 + }}$ 


Nernst Equation

It establishes a link between electrode voltage and ion concentration. When a result, as the concentration of ions rises, so does the reduction potential. For a type of generic electrochemical reaction.


$aA + bB\xrightarrow{{n{e^ - }}}cC + dD$ 


Nernst equation can be given as:


${E_{{\text{cell}}}} = E_{{\text{call}}}^0 - \dfrac{{RT}}{{nF}}\ln \dfrac{{{{[C]}^c}{{[D]}^d}}}{{{{[A]}^a}{{[B]}^b}}}$


 ${E_{c \in l}} = E_{cdl}^ \circ  - \dfrac{{2303}}{{nF}}RT\log \dfrac{{{{[C]}^c}{{[D]}^d}}}{{{{[A]}^a}{{[B]}^b}}}$


Substituting the values of R and F we get:


 ${E_{{\text{cell}}}} = E_{ccll}^0 - \dfrac{{0.0591}}{n}\log \dfrac{{{{[C]}^c}{{[D]}^d}}}{{{{[A]}^a}{{[B]}^b}}}$


Applications of Nernst Equation

Equilibrium Constant from Nernst Equation


For a Daniel Cell, at equilibrium


${{E_{{\text{cell}}}} = 0 = E_{{\text{cell}}}^0 - \dfrac{{2.303{\text{RT}}}}{{2{\text{F}}}}\log \dfrac{{\left[ {{\text{Z}}{{\text{n}}^{2 + }}} \right]}}{{\left[ {{\text{C}}{{\text{u}}^{2 + }}} \right]}}}$


${{\text{E}}_{{\text{cdl}}}^{\text{o}} = \dfrac{{2.303{\text{RT}}}}{{2{\text{F}}}}\log \dfrac{{\left[ {{\text{Z}}{{\text{n}}^{2 + }}} \right]}}{{\left[ {{\text{C}}{{\text{u}}^{2 + }}} \right]}}}$ 


But at equilibrium:


 $\dfrac{{\left[ {Z{n^{2 + }}} \right]}}{{\left[ {C{u^{2 + }}} \right]}} = {K_c}$


${{\text{E}}_{cell}^{\text{a}} = \dfrac{{2.303{\text{RT}}}}{{2{\text{F}}}}\log {{\text{K}}_{\text{c}}}}$


${{\text{E}}_{cell}^{\text{o}} = \dfrac{{2.303 \times 8.314 \times 298}}{{2 \times 96500}}\log {{\text{K}}_{\text{c}}}}$


  ${ = \dfrac{{0.0591}}{2}\log {{\text{K}}_{\text{c}}}}$ 


In general:


${{\text{E}}_{{\text{cell}}}^ \circ  = \dfrac{{0.0591}}{{\text{n}}}\log {{\text{K}}_{\text{c}}}}$ 


${\log {{\text{K}}_{\text{c}}} = \dfrac{{{\text{n}}E_{{\text{cell}}}^ \circ }}{{0.0591}}}$


Concentration Cells

Concentration cells are formed when two electrodes of the same metal are dipped individually into two solutions of the same electrolyte with varying concentrations and the solutions are connected by a salt bridge. As an example:


${H_2}|{H^ + }({C_1})||{H^ + }({C_2})|{H_2}$ 


$Cu|C{u^{ + 2}}({C_1})||C{u^{2 + }}({C_2})|Cu$ 


These Are of Two Types:

Electrode Concentration Cells

${H_2}({P_1})|{H^ + }(C)||{H^ + }(C)|{H_2}({P_2})$ 


${E_{{\text{cell}}}} = 0 - \dfrac{{0.059}}{n}\log \dfrac{{{P_2}}}{{{P_1}}}$


Where, ${P_2} < {P_1}$ for spontaneous reaction.


Electrolyte Concentration Cell

The EMF of concentration cell at 298 K is given by:


$Zn|Z{n^{2 + }}({C_1})||Z{n^{2 + }}({C_2})|Zn$ 


${{\text{E}}_{{\text{cell}}}} = \dfrac{{0.0591}}{{{{\text{n}}_1}}}\log \dfrac{{{{\text{c}}_2}}}{{{{\text{c}}_{\text{l}}}}}$


Where, ${C_2} > {C_1}$ for spontaneous reaction


Cases of Electrolysis

Electrolysis of Molten Sodium Chloride

$2NaCl(l) \rightleftharpoons 2N{a^ + }(l) + 2C{l^ - }(l)$

 

The reactions occurring at the two electrodes may be shown as follows:


At cathode: $2N{a^ + } + 2{e^ - } \to 2Na$ , ${E^ \circ } =  - 2.71\;V$

 

At anode: $2C{l^ - } \to C{l_2} + 2{e^ - }$ , ${E^ \circ } =  - 1.36\;V$ 


Overall reaction:


$2N{a^ + }(l) + 2C{l^ - }\xrightarrow{{electrolysis}}2Na(l) + C{l_2}(g)$ OR


$2NaCl(l)\xrightarrow{{electrolysis}}2Na(l) + C{l_2}(g)$ 


Electrolysis of an aqueous solution of Sodium Chloride


$NaCl(aq) \to N{a^ + }(aq) + C{l^ - }(aq)$ 


${H_2}O(l) \rightleftharpoons {H^ + }(aq) + O{H^ - }(aq)$ 


At cathode:


$2N{a^ + } + 2{e^ - } \to 2Na$ , ${E^ \circ } =  - 2.71\;V$ 


$2{H_2}O + 2{e^ - } \to {H_2} + 2O{H^ - }$ , ${E^ \circ } =  - 0.83\;V$ 


Thus ${H_2}$  gas is evolved at cathode value $N{a^ + }$  ions remain in solution.


At Anode:


$2{H_2}O \to {O_2} + 4{H^ + } + 4{e^ - }$ , ${E^ \circ } =  - 1.23\;V$

 

$2C{l^ - } \to C{l_2} + 2{e^ - }$ , ${E^ \circ } =  - 1.36\;V$ 


Thus, $C{l_2}$  gas is evolved at the anode by over voltage concept while $O{H^ - }$  ions remain in the solution.


Batteries

The term "battery" refers to a configuration in which Galvanic cells are connected in series to achieve a higher voltage.


Primary Batteries

Primary cells can be employed indefinitely as long as active components are present. When they're gone, the cell stops working and can't be used again. For instance, a Dry Cell or a Leclanche Cell, as well as a Mercury Cell.


Dry Cell

Anode: Zinc container


Cathode: Carbon (graphite) rod surrounded by powdered $Mn{O_2}$ and carbon


Electrolyte: $N{H_4}Cl$ and $ZnC{l_2}$ 


Reaction:


Anode: $Zn \to Z{n^{2 + }} + 2{e^ - }$ 


Cathode: $Mn{O_1} + NH_{_4}^ +  + {e^ - } \to MnO(OH) + N{H_3}$ 


The standard potential of this cell is 1.5 V, which decreases as the battery is repeatedly discharged, and it cannot be refilled once used.


Mercury Cells

These are used in small equipments like watches, hearing aids.


Anode: $Zn - Hg$ Amalgam


Cathode: Paste of $HgO$ and carbon


Electrolyte: Paste of $KOH$ and $ZnO$ 


Anode: $Zn(Hg) + 2O{H^ - } \to ZnO(s) + {H_2}O + 2{e^ - }$

 

Cathode: $HgO(s) + {H_2}O + 2{e^ - } \to Hg(l) + 2O{H^ - }$ 


Overall Reaction: $Zn(Hg) + HgO(s) \to ZnO(s) + Hg(l)$ 


The cell potential is approximately 1.35 V and remains constant during its life.

Secondary Batteries


Secondary batteries are rechargeable for many applications and can be recharged multiple times. Lead storage batteries and $Ni - Cd$  batteries, for example.


Lead Storage Battery

Anode: Lead $(Pb)$ 


Cathode: Grid of lead packed with lead oxide $(Pb{O_2})$ 


Electrolyte: 38% solution of ${H_2}S{O_4}$ 


Discharging Reaction


Anode: $Pb(s) + SO_4^{2 - }(aq) \to PbS{O_4}(s) + 2{e^ - }$ 


Cathode: $Pb{O_2}(s) + 4{H^ + }(aq) + SO_4^{2 - }(aq) + 2{e^ - } \to PbS{O_4}(s) + 2{H_2}O(l)$ 


Overall Reaction: $Pb(s) + Pb{O_2}(s) + 2{H_2}S{O_4}(aq) \to 2PbS{O_4}(s) + 2{H_2}O(l)$ 


To recharge the cell, it is connected to a higher-potential cell, which acts as an electrolytic cell and reverses the processes. At the relevant electrodes, $Pb(s)$  and $Pb{O_2}(s)$  are regenerated. These cells produce a voltage that is nearly constant.


Recharging Reaction: $2PbS{O_4}(s) + 2{H_2}O(l) \to Pb(s) + Pb{O_2}(s) + 2{H_2}S{O_4}(aq)$

 

Fuel Cells

A fuel cell varies from a traditional battery in that the reactants are supplied externally from a reservoir rather than being stored inside the cell. In space vehicles, fuel cells are employed, and the two gases are supplied from external storage. The electrodes in this cell are carbon rods, and the electrolyte is $KOH$ .


Cathode: ${O_2}(g) + 2{H_2}O(l) + 4{e^ - } \to 4O{H^ - }(aq)$

 

Anode: $2{H_2}(g) + 4O{H^ - }(aq) \to 4{H_2}O(l) + 4{e^ - }$ 


Overall Reaction: $2{H_2}(g) + {O_2}(g) \to 2{H_2}O(l)$


Fuel Cells


Corrosion

On the surface of iron or any other metal, it entails a redox process and the development of an electrochemical cell.


The oxidation of iron (anode) occurs at one point, while the reduction of oxygen to generate water occurs at another (cathode). $Fe$  is first oxidised to $F{e^{2 + }}$ , which is then converted to $F{e^{3 + }}$  in the presence of oxygen, which subsequently combines with water to generate rust, which is represented by $F{e_2}{O_3}.x{H_2}O$ .


Anode: $2Fe(s) \to 2F{e^{2 + }} + 4{e^ - }$ , ${E^ \circ } =  + 0.44\;V$ 


Cathode: ${O_2}(g) + 4{H^ + } + 4{e^ - } \to 2{H_2}O(l)$ , ${E^ \circ } = 1.23\;V$ 


Overall Reaction: $2Fe(s) + {O_2}(g) + 4{H^ + } \to 2F{e^{2 + }} + 2{H_2}O$ , $E_{Cell}^ \circ  = 1.67\;M$ 


A redox process and the development of an electrochemical cell on iron metal


Painting or coating iron with other metals, such as zinc, helps prevent it from rusting. Galvanisation is the name for the latter procedure. Because $Zn$  has a higher potential to oxidise than iron, it is oxidised first, while iron is protected. Cathodic Protection is another name for this approach of shielding one metal by the other.


A redox process and the development of an electrochemical cell on  iron metal


Conductance (G)

It is defined as the ease with which electric current passes through a conductor and is the reciprocal of resistance.


$G = \dfrac{1}{R}$ 


SI unit is Siemen (S).


$1\;S = 1\;oh{m^{ - 1}}(mho)$ 


Conductivity 

It is the reciprocal of resistivity $(\rho )$ .


$\kappa  = \dfrac{1}{\rho } = \dfrac{1}{R} \times \dfrac{\ell }{A} = G \times \dfrac{\ell }{A}$


Now is $l = 1\;cm$ and $A = 1\;c{m^2}$ , then $\kappa  = G$

 

 As a result, the conductivity of an electrolytic solution can be defined as the conductance of a $1\;cm$  long solution with a $1\;c{m^2}$  cross-sectional area.


Factors Affecting Electrolyte Conductance

Electrolyte

In a dissolved or molten form, an electrolyte is a substance that dissociates in solution to produce ions and hence conducts electricity.


Examples: $HCl,\;NaOH,\;KCl$ are strong electrolytes and $C{H_3}COOH,\;N{H_4}OH$ are weak electrolytes.


Electrolytic or ionic conductance refers to the conductance of electricity by ions present in solutions. The flow of electricity through an electrolyte solution is governed by the following factors.

  1. Electrolyte Nature or Interionic Attractions: The lower the solute-solute interactions, the larger the freedom of ion mobility and the higher the conductance.

  2. Ion Solvation: As the amount of solute-solvent interactions increases, the extent of solvation increases, and the electrical conductance decreases.

  3. The Nature of the Solvent and its Viscosity: The larger the solvent-solvent interactions, the higher the viscosity, and the greater the solvent's resistance to ion flow, and thus the lower the electrical conductance.

  4. Temperature: As the temperature of an electrolytic solution rises, solute-solute, solute-solvent, and solvent-solvent interactions diminish, causing electrolytic conductance to rise.


Measurement of Conductance

As we know, $\kappa  = \dfrac{1}{{\text{R}}} \times \dfrac{\ell }{{\text{A}}}$ 

 If we measure $l$ , $A$ , and $R$ , we can figure out what the value of $\kappa $  is. Using the ‘Wheatstones' bridge method, the resistance of the solution $R$  between two parallel electrodes is calculated.


Measurement of Conductance


It is made up of two fixed resistances, R3 and R4, a variable resistance R1, and a conductivity cell with an unknown resistance, R2. When no current goes through the detector, the bridge is balanced. Then, in these circumstances:


$\dfrac{{{R_1}}}{{{R_2}}} = \dfrac{{{R_3}}}{{{R_4}}}$  or ${R_2} = \dfrac{{{R_1}{R_4}}}{{{R_3}}}$ 


Molar Conductivity

It's the total conducting power of all the ions created by dissolving one mole of an electrolyte between two big electrodes separated by one centimetre.


Mathematically,

\[\Lambda_{m} = \kappa \times V, \Lambda_{m} = \frac{\kappa \times V}{C}\]


where, V is the volume of solution in $c{m^3}$  containing 1 mole of electrolyte and C is the molar concentration.


Units: \[\Lambda_{m} = \frac{\kappa \times V}{C} = \frac{\text{S }cm^{-1}}{\text{mol } cm^{-1}}\]


${ = {\text{oh}}{{\text{m}}^{ - 1}}{\text{c}}{{\text{m}}^2}{\text{mo}}{{\text{l}}^{ - 1}}{\text{orSc}}{{\text{m}}^2}{\text{mo}}{{\text{l}}^{ - 1}}}$ 


Equivalent Conductivity

It is the electrical conductivity of one equivalent electrolyte placed between two big electrodes separated by one centimetre.


Mathematically:

${{{{\Lambda }}_{{\text{eq}}}} = \kappa  \times {\text{v}} = }$


${{{{\Lambda }}_{{\text{eq}}}} = \dfrac{{\kappa  \times 1000}}{{\text{N}}}}$


Where, v is the volume of solution in $c{m^3}$  containing 1 equivalent of electrolyte and N is normality.


Units:

${{{{\Lambda }}_{{\text{eq}}}} = \dfrac{{\kappa  \times 1000}}{{\text{N}}}}$


${ = \dfrac{{{\text{Sc}}{{\text{m}}^{ - 1}}}}{{{{\;equivalent\;c}}{{\text{m}}^{ - 3}}}} = \dfrac{{{\text{Oh}}{{\text{m}}^{ - 1}}{\text{c}}{{\text{m}}^2}{{\;equivalent}}{{{\;}}^{ - 1}}}}{{{\text{Sc}}{{\text{m}}^2}{{\;equivalent}}{{{\;}}^{ - 1}}}}}$


Variation of Conductivity and Molar Conductivity with Dilution

Because the number of ions per unit volume that carry the current in the solution reduces as concentration lowers, conductivity drops. With a decrease in concentration, molar conductivity rises. This is due to an increase in the total volume V of a solution containing one mole of electrolyte. The drop in $\kappa $  as a result of dilution of a solution has been found to be more than compensated by increases in its volume.


Graphical representation of the variation of ${\Lambda _m}$ vs $\sqrt c $ .


Variation of Conductivity and Molar Conductivity with Dilution


Limiting Molar Conductivity $({\Lambda _m})$ 

Limiting molar conductivity, also known as molar conductivity at infinite dilution, is the value of molar conductivity as the concentration approaches zero. In the case of a strong electrolyte, extrapolation of the ${\Lambda _m}$  vs $\sqrt c $  curve can be used to derive the molar conductivity at infinite dilution. Extrapolation of the curve, on the other hand, cannot be used to calculate the value of molar conductivity of a weak electrolyte at infinite dilution since the curve becomes practically parallel to the y-axis as concentration approaches zero.


The mathematical relationship between ${\Lambda _m}$  and $\Lambda _m^ \circ $  for a strong electrolyte was developed by Debye, Huckel and Onsagar.

 

In simplified form the equation can be given as:


${{t{\Lambda }}_{\text{m}}} = {{\Lambda }}_{\text{m}}^\infty  - {\text{b}}{{\text{c}}^{1/2}}$


Kohlrausch’s Law

 It asserts that an electrolyte limiting molar conductivity can be described as the total of the individual contributions of the electrolyte's anion and cation.

In general, if an electrolyte produces ${v_ + }$  cations and ${v_ - }$  anions upon dissociation, its limiting molar conductivity is given by:


${{\Lambda }}_{\text{m}}^\infty  = {{\text{v}}_ + }\lambda _ + ^ \circ  + {{\text{v}}_ - }\lambda _ - ^ \circ $


Applications of Kohlrausch’s Law

  1. Calculation of molar conductivities of weak electrolyte at infinite dilution

 For example, the molar conductivity of acetic acid at infinite dilution can be calculated using the molar conductivities of strong electrolytes like $HCl$ , $C{H_3}COONa$ , and $NaCl$  at infinite dilution, as shown below.


${{\Lambda }}_{{\text{m}}\left( {{\text{C}}{{\text{H}}_3} - {\text{COOH}}} \right)}^{\text{o}} = {{\Lambda }}_{{\text{m}}\left( {{\text{C}}{{\text{H}}_3} - {\text{cooNa}}} \right)}^{\text{o}} + {{\Lambda }}_{{\text{m}}({\text{HCl}})}^{\text{o}} - {{\Lambda }}_{{\text{m}}({\text{NaCl}})}^ \circ $


  1. Determination of Degree of Dissociation of Weak Electrolytes

 Degree of dissociation $\alpha  = \dfrac{{\Lambda _m^c}}{{\Lambda _m^ \circ }}$ 


  1. Determination of Dissociation Constant of Weak Electrolytes:

${{\text{K}} = \dfrac{{{\text{c}}{\alpha ^2}}}{{1 - \alpha }}}$


${\alpha  = \dfrac{{{{\Lambda }}_{\text{m}}^{\text{c}}}}{{{{\Lambda }}_{\text{m}}^\infty }}}$


${{\text{K}} = \dfrac{{{\text{c}}{{\left( {{{\Lambda }}_{\text{m}}^{\text{c}}/{{\Lambda }}_{\text{m}}^\infty } \right)}^2}}}{{1 - {{\Lambda }}_{\text{m}}^c/{{\Lambda }}_{\text{m}}^\infty }} = \dfrac{{{\text{C}}{{\left( {{{\Lambda }}_{\text{m}}^{\text{c}}} \right)}^2}}}{{{{\Lambda }}_{\text{m}}^\infty \left( {{{\Lambda }}_{\text{m}}^ *  - {{\Lambda }}_{\text{m}}^{\text{c}}} \right)}}}$ 


Use of $\Delta G$ in Relating EMF values of Half Cell Reactions

When we have two half-cell reactions that produce another half-cell reaction when we combine them, their emfs cannot be mixed directly. However, thermodynamic functions such as $\Delta G$  can be added and EMF values can be connected through them in any scenario. Take a look at the three half-cell responses below:


$F{e^{2 + }} + 2{e^ - } \to Fe$ , ${E_1}$

 

$F{e^{3 + }} + 3{e^ - } \to Fe$ , ${E_2}$

 

$F{e^{3 + }} + {e^ - } \to F{e^{2 + }}$ , ${E_3}$ 


We can clearly see that subtracting the first reaction from the second yields the third reaction. However, the same relationship does not hold true for EMF values. 


That is: ${E_3} \ne {E_2} - {E_1}$ . But the $\Delta G$ values can be related according to the reactions:


${{{\Delta }}{{\text{G}}_3} = {\text{\Delta }}{{\text{G}}_2} - {{\Delta }}{{\text{G}}_1}}$


${ - {{\text{n}}_3}{\text{F}}{{\text{E}}_3} =  - {{\text{n}}_2}{\text{F}}{{\text{E}}_2} + {{\text{n}}_1}{\text{F}}{{\text{E}}_1}}$

  ${ - {{\text{E}}_3} =  - 3{{\text{E}}_2} + 2{{\text{E}}_1}}$


  ${ \Rightarrow {{\mathbf{E}}_3} = 3{{\mathbf{E}}_2} - {\mathbf{2}}{{\mathbf{E}}_1}}$ 


Formula:

  1. ${\text{R}} = \rho \left( {\dfrac{\ell }{{\text{A}}}} \right) = \rho  \times {\text{Cell constant}}$

Where, $R$ = Resistance, 

$A$ = Area of cross-section of the electrodes

$\rho $ = Resistivity

  1.  $\kappa  = \dfrac{1}{{\text{R}}} \times {\text{\;cell constant\;}}$

Where, $\kappa $ = Conductivity or specific conductance

  1. ${{{\Lambda }}_{\text{m}}} = \dfrac{{\kappa  \times 1000}}{{\text{M}}}$

Where, ${\Lambda _m}$ = Molar conductivity 

$M$ = Molarity of the solution.

  1. ${{\Lambda }}_m^\infty \left( {{A_x}{B_y}} \right) = x{{\Lambda }}_m^\infty \left( {{A^y}} \right) + y{\text{\Lambda }}_m^\infty \left( {{B^{x - }}} \right)$

  2.  $\alpha  = \dfrac{{\Lambda _m^c}}{{\Lambda _m^ \circ }}$

Where, $\alpha $ = Degree of dissociation

$\Lambda _m^c$ = Molar conductivity at a given concentration

  1. For a weak binary electrolyte AB

${\text{K}} = \dfrac{{{\text{c}}{\alpha ^2}}}{{1 - \alpha }} = \dfrac{{{\text{c}}{{\left( {{{\Lambda }}_{\text{m}}^{\text{c}}} \right)}^2}}}{{{{\Lambda }}_{\text{m}}^\infty \left( {{{\Lambda }}_{\text{m}}^\infty  - {{\Lambda }}_{\text{m}}^{\text{c}}} \right)}}$

Where, K is the Dissociation constant

${{\text{E}}_{{\text{edl}}}^ \circ  = {\text{E}}_{{\text{cathode}}}^ \circ  + {\text{E}}_{{\text{anode}}}^ \circ }$

${ = {{\text{E}}^ \circ }{\text{Right}} + {{\text{E}}^{\text{o}}}{\text{left}}}$

  1. Nernst equation for a generation electrochemical reation

${E_{{\text{ofll}}}} = E_{{\text{cell}}}^ \circ  - \dfrac{{0.059}}{n}\log \dfrac{{{{[A]}^2}{{[B]}^b}}}{{{{[C]}^c}{{[D]}^d}}}$

  1.  $\log {{\text{K}}_{\text{c}}} = \dfrac{{\text{n}}}{{0.0591}}{\text{E}}_{{\text{cell}}}^ \circ $

Where, ${K_c}$ = Equilibrium constant.

  1. ${{{\Delta }}_r}{{\text{G}}^ \circ } =  - {\text{nFE}}_{{\text{cell}}}^ \circ $

${{{\Delta }}_{\text{r}}}{{\text{G}}^ \circ } =  - 2.303{\text{RT}}\log {{\text{K}}_{\text{c}}}$

${\Delta _r}{G^ \circ }$ = Standard Gibbs energy of a reaction

  1. $Q = I \times t$ 

Where, $Q$ = Quantity of charge in coulombs

$I$ = Current in amperes

$t$ = Time in seconds

  1. $m = Z \times I \times t$ 

Where, $m$ = mass of the substance liberated at the electrodes

$Z$ = Electrochemical equivalent

Standard Reduction Potential At 298 K. In Electrochemical Order

$\mathrm{H}_{4} \mathrm{XeO}_{6}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{XeO}_{3}+3 \mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad+3.0$


$\mathrm{~F}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{~F}^{-}  \quad\quad\quad\quad+2.87$


$\mathrm{O}_{3}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{O}_{2}+\mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad +2.07$


$\mathrm{~S}_{2} \mathrm{O}_{8}^{2-}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{SO}_{4}^{2-} \quad\quad\quad\quad +2.05$


$\mathrm{Ag}^{2+}+\mathrm{c}^{-} \rightarrow \mathrm{Ag}^{+} \quad\quad\quad\quad +1.98$


$\mathrm{Co}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Co}^{2+} \quad\quad\quad\quad +1.81$


$\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad +1.78$


$\mathrm{Au}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Au} \quad\quad\quad\quad +1.69$


$\mathrm{~Pb}^{4+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pb}^{2+} \quad\quad\quad\quad +1.67$


$2 \mathrm{HClO}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad +1.63$


$\mathrm{Ce}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{Ce}^{3+} \quad\quad\quad\quad +1.61$


$2 \mathrm{H} \mathrm{IBrO}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Br}_{2}+2 \mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad +1.60$


$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad +1.51$


$\mathrm{Mn}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+} \quad\quad\quad\quad +1.51$


$\mathrm{Au}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Au} \quad\quad\quad\quad +1.40$


$\mathrm{Cl}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cl}^{-} \quad\quad\quad\quad +1.36$


$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad +1.33$


$\mathrm{O}_{3}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{O}_{2}+2 \mathrm{OH}^{-} \quad\quad\quad\quad +1.24$


$\mathrm{O}_{2}+4 \mathrm{H}^{+} 4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \quad\quad\quad\quad +1.23$


$\mathrm{Hg}_{2} \mathrm{SO}_{4}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Hg}+\mathrm{SO}_{4}^{2-} \quad \quad \quad \quad +0.62$


$\mathrm{MnO}_{4}^{2-}+2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{MnO}_{2}+4 \mathrm{OH}^{-} \quad \quad \quad \quad +0.60$


$\mathrm{MnO}_{4}^{-}+\mathrm{e}^{-} \rightarrow \mathrm{MnO}_{4}^{2-} \quad \quad \quad \quad +0.56$


$\mathrm{I}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{I}^{-} \quad \quad \quad \quad +0.54$


$\mathrm{Cu}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu} \quad \quad \quad \quad +0.52$


$\mathrm{I}_{3}^{-}+2 \mathrm{e}^{-} \rightarrow 3 \mathrm{I}^{-} \quad \quad \quad \quad +0.53$


$\mathrm{NiOOH}+\mathrm{H}_{2} \mathrm{O}+\mathrm{e}^{-} \rightarrow \mathrm{Ni}(\mathrm{OH})_{2}+\mathrm{OH}^{-} \quad \quad \quad \quad +0.49$


$\mathrm{Ng}_{2} \mathrm{CrO}_{4}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Ag}+\mathrm{CrO}_{4}^{2-} \quad \quad \quad \quad +0.45$


$\mathrm{O}_{2}+2 \mathrm{H}_{2} \mathrm{O}+4 \mathrm{e}^{-} \rightarrow 4 \mathrm{OH}^{-} \quad \quad \quad \quad +0.40$


$\mathrm{ClO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +0.36$


${\left[\mathrm{Fe}(\mathrm{CN})_{6}^{3-}+\mathrm{e}^{-} \rightarrow\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{+}\right.} \quad \quad \quad \quad +0.36$


$\mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu} \quad \quad \quad \quad +0.34$


$\mathrm{Hg}_{2} \mathrm{Cl}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Hg}+2 \mathrm{Cl}^{-} \quad \quad \quad \quad +0.27$


$\mathrm{AgCl}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}+\mathrm{Cl}^{-} \quad \quad \quad \quad +0.22$


$\mathrm{Bi}+3 \mathrm{e}^{-} \rightarrow \mathrm{Bi} \quad \quad \quad \quad +0.20$


$\mathrm{Cu}^{2+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu}^{+} \quad \quad \quad \quad +0.16$


$\mathrm{Sn}^{4+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sn}^{2+} \quad \quad \quad \quad +0.15$


$\mathrm{AgBr}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}+\mathrm{Br}^{-} \quad \quad \quad \quad +0.07$


$\mathrm{ClO}_{4}^{-}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+\mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.23$


$\mathrm{MNO}_{2}+4 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.23$


$\mathrm{Br}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Br}^{-} \quad \quad \quad \quad +1.09$


$\mathrm{Pu}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{Pu}^{3+} \quad \quad \quad \quad +0.97$


$\mathrm{NO}_{3}^{-}+4 \mathrm{H}^{+}+3 \mathrm{e}^{-} \rightarrow \mathrm{NO}+2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +0.96$


$2 \mathrm{Hg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Hg}_{2}^{2+} \quad \quad \quad \quad +0.92$


$\mathrm{ClO}^{-}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cl}^{-}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +0.89$


$\mathrm{Hg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Hg} \quad \quad \quad \quad +0.86$


$\mathrm{NO}_{3}^{-}+2 \mathrm{H}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{NO}_{2}+\mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +0.80$


$\mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag} \quad \quad \quad \quad +0.80$


$\mathrm{Hg}_{2}^{2+}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Hg} \quad \quad \quad \quad +0.79$


$\mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+} \quad \quad \quad \quad +0.77$


$\mathrm{BrO}^{-}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{Br}^{-}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +0.76$


$\mathrm{Ti}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{Ti}^{3+} \quad \quad \quad \quad 0.00  2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \quad \quad \quad \quad 0, \text { by definition }$

 

$\mathrm{Fe}^{3-}+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \quad \quad \quad \quad -0.04$


$\mathrm{O}_{2} \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{HO}_{2}^{-}+\mathrm{OH}^{-} \quad \quad \quad \quad -0.08$

 

$\mathrm{~Pb}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pb} \quad \quad \quad \quad -0.13$


$\mathrm{In}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{In} \quad \quad \quad \quad -0.14$


$\mathrm{Sn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sn} \quad \quad \quad \quad -0.14$


$\mathrm{AgI}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}+\mathrm{F}^{-} \quad \quad \quad \quad -0.15$


$\mathrm{Ni}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni} \quad \quad \quad \quad -0.23$


$\mathrm{Co}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Co} \quad \quad \quad \quad -0.28$


$\mathrm{In}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{In} \quad \quad \quad \quad -0.34$ 


$\mathrm{Tl}^{+}\mathrm{e}^{-} \rightarrow \mathrm{Tl} \quad \quad \quad \quad -0.34$


$\mathrm{PbSO}_{4}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pb}+\mathrm{SO}_{4}^{2-} \quad \quad \quad \quad -0.36$


$\mathrm{Ti}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Ti}^{2+} \quad \quad \quad \quad -0.37$


$\mathrm{Cd}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cd} \quad \quad \quad \quad -0.40$


$\mathrm{In}^{2+}+\mathrm{e}^{-} \rightarrow \mathrm{In}^{+} \quad \quad \quad \quad -0.40$


$\mathrm{Cr}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Cr}^{2+} \quad \quad \quad \quad -0.41$


$\mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \quad \quad \quad \quad -0.44$


$\mathrm{In}^{3+}+2 \mathrm{e}^{-} \rightarrow \mathrm{In}^{+} \quad \quad \quad \quad -0.44$


$\mathrm{~S}+2 \mathrm{e}^{-} \rightarrow \mathrm{S}^{2-} \quad \quad \quad \quad -0.48$


$\mathrm{In}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{In}^{2+} \quad \quad \quad \quad -0.49$


$\mathrm{U}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{U}^{3+} \quad \quad \quad \quad -0.61$


$\mathrm{Cr}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Cr} \quad \quad \quad \quad -0.74$


$\mathrm{Zn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Zn} \quad \quad \quad \quad -0.76$


$\mathrm{Cd}(\mathrm{OH})_{2}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cd}+2 \mathrm{OH}^{-} \quad \quad \quad \quad -0.81$


$2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2}+2 \mathrm{OH}^{-} \quad \quad \quad \quad -0.83$


$\mathrm{Cr}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cr} \quad \quad \quad \quad -0.91$


$\mathrm{Mn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mn} \quad \quad \quad \quad -1.18$


$\mathrm{V}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{V} \quad \quad \quad \quad -1.19$ 


$\mathrm{Ti}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ti} \quad \quad \quad \quad -1.63$ 


$\mathrm{Al}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Al} \quad \quad \quad \quad -1.66$ 


$\mathrm{U}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{U} \quad \quad \quad \quad -1.79$ 


$\mathrm{Sc}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Sc} \quad \quad \quad \quad -2.09$ 


$\mathrm{Mg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mg} \quad \quad \quad \quad -2.36$ 


$\mathrm{Ce}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Ce} \quad \quad \quad \quad -2.48$ 


$\mathrm{La}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{La} \quad \quad \quad \quad -2.52$ 


$\mathrm{Na}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Na} \quad \quad \quad \quad -2.71$ 


$\mathrm{Ca}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ca} \quad \quad \quad \quad -2.87$ 


$\mathrm{Sr}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sr} \quad \quad \quad \quad -2.89$ 


$\mathrm{Ba}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ba} \quad \quad \quad \quad -2.91$

 

$\mathrm{Ra}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ra} \quad \quad \quad \quad -2.92$ 


$\mathrm{Cs}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Cs} \quad \quad \quad \quad -2.92$ 


$\mathrm{Rb}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Rb} \quad \quad \quad \quad -2.93$ 


$\mathrm{~K}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{K} \quad \quad \quad \quad -2.93$ 


$\mathrm{Li}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Li} \quad \quad \quad \quad -3.05$


Reduction Potential in Alphabetical Order: 

$\mathrm{Ag}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}$


$\mathrm{Ag}^{2+}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}^{+}$


$\mathrm{AgBr}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}+\mathrm{Br}^{-}$


$\mathrm{AgCl}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}+\mathrm{Cl}^{-}$


$\mathrm{Ag}_{2} \mathrm{CrO}_{4}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Ag}+\mathrm{CrO}_{4}^{2-}$


$\mathrm{AgF}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}+\mathrm{F}^{-}$


$\mathrm{Agl}+\mathrm{e}^{-} \rightarrow \mathrm{Ag}+\mathrm{I}^{-}$


$\mathrm{Al}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Al}$


$\mathrm{Au}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Au}$


$\mathrm{Au}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Au}$


$\mathrm{Ba}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ba}$


$\mathrm{Be}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Be}$


$\mathrm{Bi}^{-3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Bi}$


$\mathrm{Br}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Br}^{-}$


$\mathrm{BrO}^{-}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{Br}^{-}+2 \mathrm{OH}^{-}$


$\mathrm{Ca}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ca} \quad \quad \quad \quad -2.87$


$\mathrm{Cd}(\mathrm{OH})_{2}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cd}+2 \mathrm{OH}^{-} \quad \quad \quad \quad -0.81$


$\mathrm{Cd}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cd} \quad \quad \quad \quad -0.40$


$\mathrm{Ce}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Ce} \quad \quad \quad \quad -2.48$


$\mathrm{Ce}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{Ce}^{3+} \quad \quad \quad \quad +1.61$


$\mathrm{Cl}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cl}^{-} \quad \quad \quad \quad +1.36$


$\mathrm{ClO}^{-}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cl}^{-}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +0.89$


$\mathrm{ClO}_{4}^{-}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+\mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.23$


$\mathrm{ClO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{ClO}_{3}^{-}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +0.36$


$\mathrm{Co}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Co} \quad \quad \quad \quad -0.28$


$\mathrm{Co}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Co}^{2+} \quad \quad \quad \quad +1.81$


$\mathrm{Cr}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cr} \quad \quad \quad \quad -0.91$


$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.33$


$\mathrm{Cr}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Cr} \quad \quad \quad \quad -0.74$


$\mathrm{Cr}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Cr}^{2+} \quad \quad \quad \quad -0.41$


$\mathrm{Cs}^{+} \mathrm{e}^{-} \rightarrow \mathrm{Cs} \quad \quad \quad \quad -2.92$


$\mathrm{Cu}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu} \quad \quad \quad \quad +0.52$


$\mathrm{Cu}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu} \quad \quad \quad \quad +0.34$


$\mathrm{Cu}^{2+}+\mathrm{e}^{-} \rightarrow \mathrm{Cu}^{+} \quad \quad \quad \quad +0.16$


$\mathrm{~F}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{~F}^{-} \quad \quad \quad \quad +2.87$


$\mathrm{Fe}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \quad \quad \quad \quad -0.44$


$\mathrm{Fe}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Fe} \quad \quad \quad \quad -0.04$


$\mathrm{Fe}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+} \quad \quad \quad \quad +0.77$


${\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3}+\mathrm{e}^{-} \rightarrow\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{+}} \quad \quad \quad \quad +0.36$


$2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \quad \quad \quad \quad 0, \text { by definition }$


$2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2}+2 \mathrm{OH}^{-} \quad \quad \quad \quad -0.83$


$2 \mathrm{HBrO}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Br}_{2}+2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.60$


$2 \mathrm{HClO}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.63$


$\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.78$


$\mathrm{H}_{4} \mathrm{XeO}_{6}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{XeO}_{3}+3 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +3.0$


$\mathrm{MnO}_{4}^{-}+2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{MnO}_{2}+4 \mathrm{OH}^{-} \quad \quad \quad \quad +0.60$


$\mathrm{Na}^{-}+\mathrm{e}^{-} \rightarrow \mathrm{Na} \quad \quad \quad \quad -2.71$


$\mathrm{Ni}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni} \quad \quad \quad \quad -0.23$


$\mathrm{NiOOH}+\mathrm{H}_{2} \mathrm{O}+\mathrm{e}^{-} \rightarrow \mathrm{Ni}(\mathrm{OH})_{2}+\mathrm{OH}^{-} \quad \quad \quad \quad +0.49$


$\mathrm{NO}_{3}^{-}+2 \mathrm{H}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{NO}_{2}+\mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad -0.80$


$\mathrm{NO}_{3}^{-}+4 \mathrm{H}^{+}+3 \mathrm{e}^{-} \rightarrow \mathrm{NO}+2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +0.96$


$\mathrm{NO}_{3}^{-}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{NO}_{2}^{-}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +0.10$


$\mathrm{O}_{2}+2 \mathrm{H}_{2} \mathrm{O}+4 \mathrm{e}^{-} \rightarrow 4 \mathrm{OH}^{-} \quad \quad \quad \quad +0.40$


$\mathrm{O}_{2}+4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.23$


$\mathrm{O}_{2}+\mathrm{e}^{-} \rightarrow \mathrm{O}_{2}^{-} \quad \quad \quad \quad -0.56$


$\mathrm{O}_{2}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{HO}_{2}^{-}+\mathrm{OH}^{-} \quad \quad \quad \quad -0.08$


$\mathrm{O}_{3}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{O}_{2}+\mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +2.07$


$\mathrm{O}_{3}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{O}_{2}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +1.24$


$\mathrm{H}_{4} \mathrm{XeO}_{6}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{XeO}_{3}+3 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +3.0$


$\mathrm{Hg}_{2}^{2+}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Hg} \quad \quad \quad \quad +0.79$


$\mathrm{Hg}_{2} \mathrm{Cl}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Hg}+2 \mathrm{Cl}^{-} \quad \quad \quad \quad +0.27$


$\mathrm{Hg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Hg} \quad \quad \quad \quad +0.86$


$2 \mathrm{Hg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Hg}_{2}^{2+} \quad \quad \quad \quad +0.92$


$\mathrm{Hg}_{2} \mathrm{SO}_{4}+2 \mathrm{e}-\rightarrow 2 \mathrm{Hg}+\mathrm{SO}_{4}^{2-} \quad \quad \quad \quad +0.62$


$\mathrm{I}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{I}^{-} \quad \quad \quad \quad +0.54$


$\mathrm{I}_{3}^{-}+2 \mathrm{e}^{-} \rightarrow 3 \mathrm{I}^{-} \quad \quad \quad \quad +0.53$


$\mathrm{In}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{In} \quad \quad \quad \quad -0.14$


$\mathrm{In}^{2+}+\mathrm{e}^{-} \rightarrow \mathrm{In}^{+} \quad \quad \quad \quad -0.40$


$\mathrm{In}^{3+}+2 \mathrm{e}^{-} \rightarrow \mathrm{In}^{+} \quad \quad \quad \quad -0.44$


$\mathrm{In}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{In} \quad \quad \quad \quad -0.34$


$\mathrm{In}^{3+}+\mathrm{c}^{-} \rightarrow \mathrm{In}^{2+} \quad \quad \quad \quad -0.49$


$\mathrm{~K}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{K} \quad \quad \quad \quad -2.93$


$\mathrm{La}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{La} \quad \quad \quad \quad -2.52$


$\mathrm{Li}+\mathrm{e}^{-} \rightarrow \mathrm{Li} \quad \quad \quad \quad -3.05$


$\mathrm{Mg}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mg} \quad \quad \quad \quad -2.36$


$\mathrm{Mn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{M} \quad \quad \quad \quad -1.18$


$\mathrm{Mn}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+} \quad \quad \quad \quad +1.51$


$\mathrm{MnO}_{2}+4 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+2 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.23$


$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O} \quad \quad \quad \quad +1.51$


$\mathrm{MnO}_{4}^{-}+\mathrm{e}^{-} \rightarrow \mathrm{MnO}_{4}^{2-} \quad \quad \quad \quad +0.56$


$\mathrm{O}_{3}+\mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \rightarrow \mathrm{O}_{2}+2 \mathrm{OH}^{-} \quad \quad \quad \quad +1.24$


$\mathrm{~Pb}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pb} \quad \quad \quad \quad -0.13$


$\mathrm{~Pb}^{4+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pb}^{2+} \quad \quad \quad \quad +1.67$


$\mathrm{PbSO}_{4}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pb}+\mathrm{SO}_{4}^{2-} \quad \quad \quad \quad -0.36$


$\mathrm{Pt}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Pt} \quad \quad \quad \quad +1.20$


$\mathrm{Pu}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{Pu}^{3+} \quad \quad \quad \quad +0.97$


$\mathrm{Ra}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ra} \quad \quad \quad \quad -2.92$


$\mathrm{Rb}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Rb} \quad \quad \quad \quad -2.93$


$\mathrm{~S}+2 \mathrm{e}^{-} \rightarrow \mathrm{S}^{2-} \quad \quad \quad \quad -0.48$


$\mathrm{~S}_{2} \mathrm{O}_{8}^{2-}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{SO}_{4}^{2-} \quad \quad \quad \quad +2.05$


$\mathrm{SC}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{Sc} \quad \quad \quad \quad -2.09$


$\mathrm{Sn}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sn} \quad \quad \quad \quad -0.14$


$\mathrm{Sn}^{4+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sn}^{2+} \quad \quad \quad \quad +0.15$


$\mathrm{Sr}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sr} \quad \quad \quad \quad -2.89$


$\mathrm{Ti}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ti} \quad \quad \quad \quad -1.63$


$\mathrm{Ti}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{Ti}^{2+} \quad \quad \quad \quad -0.37$


$\mathrm{Ti}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{Ti}^{3+} \quad \quad \quad \quad 0.00$


$\mathrm{Tl}^{+}+\mathrm{e}^{-} \rightarrow \mathrm{Tl} \quad \quad \quad \quad -0.34$


$\mathrm{U}^{3+}+3 \mathrm{e}^{-} \rightarrow \mathrm{U} \quad \quad \quad \quad -1.79$


$\mathrm{U}^{4+}+\mathrm{e}^{-} \rightarrow \mathrm{U}^{3+} \quad \quad \quad \quad -0.61$


$\mathrm{~V}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{V} \quad \quad \quad \quad -1.19$


$\mathrm{~V}^{3+}+\mathrm{e}^{-} \rightarrow \mathrm{V}^{2+} \quad \quad \quad \quad -0.26$


$\mathrm{Zn}^{2+}+2 \mathrm{e}-\rightarrow \mathrm{Zn} \quad \quad \quad \quad -0.76$


Some Important Questions on Electrochemistry

1. What is the meaning of the negative sign in the expression $\dfrac{E_0 Zn^{2+}}{Zn} = – 0.76 V$?

Ans. The negative sign in the given expression implies that Zn is more reactive than hydrogen or that it is a stronger reducing agent than hydrogen. Zinc will be oxidised to $Zn^{2+}$ ions, while the $H^+$ ions will get reduced to hydrogen in a cell that contains a zinc electrode and a standard hydrogen electrode present in two half-cells.


2. What are the conditions under which $E_0$ cell = 0 and $\Delta rG_0 = 0$?

Ans. When at equilibrium, $E_0$cell = 0 and $\Delta rG_0 = 0$.


3. Can we measure the absolute electrode potential of an electrode?

Ans. No, it is not possible to measure the absolute potential of an electrode since the half-cell that contains a single electrode cannot work on its own, it can only work in combination with another half-cell.

Topics Related to Electrochemistry Class 12 Notes PDF Download

Explore our curated collection of resources on Electrochemistry Class 12. Dive into concise notes, explanations, and practice questions to bolster your understanding of this essential subject. Whether you're preparing for exams or aiming to deepen your knowledge, these resources are created to support your learning journey effectively. Here is the links for a few Topics Related to Electrochemistry Class 12 Notes, that you can learn along with Class 12 Electrochemistry Notes. 


Standard Electrode Potential

EMF of Cell

Reduction Potential

Nernst Equation

Fuel Cell


For Further Assistance Watch our Master Teacher Shilpi mam Explaining Electrochemistry Full Chapter in 60 Minutes | Class 12 Chemistry. 


You can also watch Electrochemistry Class 12 One Shot by Aravind Arora Sir. 


Other Related Links


Important Electrochemistry Related Links

Explore a compilation of valuable links related to Electrochemistry topic, offering comprehensive study materials, solved examples, and practice questions for Class 12 students studying chemistry.




Important Class 12 Study Materials Links

Find a curated selection of study resources for Class 12 subjects, helping students prepare effectively and excel in their academic pursuits.




Conclusion

This article on revision notes for CBSE Class 12 Chemistry Chapter 2, which is on Electrochemistry, has been offered by Vedantu's expert professors to assist students in their never-ending hunt for exam-appropriate study resources as test dates approach. We urge that students look through the resources in this page as well as the ones in the connected links in order to achieve good grades in their class 12 chemistry examinations.

FAQs on Electrochemistry Class 12 Notes CBSE Chemistry Chapter 2 (Free PDF Download)

1. What is the Difference Between a Galvanic Cell and Electrolytic Cell?

The prime disparity between a galvanic cell and electrolytic cells are- 

An electrolytic cell has a non-spontaneous reaction which transforms into an electrical form of energy. In a galvanic cell, input energy is put to function in a redox form of response in spontaneous form.

In an electrolytic cell, the anode remains positive electrode and cathode is in negative form while it is opposite in the case of a galvanic cell. In a galvanic cell, electrons create from the class that experience oxidation while the oxidation process happens at the cathode of an electrolytic cell.

2. What is a Cell Notation?

An electrochemical cell has various uses in the general world. Therefore, a user needs to follow specific rules while representing them. The crucial parts like the cathode should always be right while an anode should stay on the left.

Here the cell is shown by following a specific rule where metals are written first, followed by metal ions. These metal ions can be found in electrolyte forms.  They are further required to be separated via a vertical structure of the line. 

An example will be  $Zn | Zn^{2+}$ . Here one can find a molar concentration that is represented via brackets. The result is  $Zn | Zn^{2+}(1M)$  .

3. What are the applications of electrochemical cells?

An electrolytic cell is used to refine electrically many of the non-ferrous metals. They are also used for electrowinning. Apart from melting metals and creating new structures, an electrochemical cell performs different reactions. 

They are also used to produce high-grade metals like aluminium, zinc, copper, etc., for general use. Furthermore, one can extract metallic sodium out of molten sodium chloride. This is possible by placing an electrolytic cell in a solution and bypassing electric current over it.

Moreover, these cells are used to produce large batteries which are used commercially like galvanic cells. The best part is that these cells can also be eco-friendly as they save the environment in the form of fuel cells.

4. How are Electrochemistry Class 12 Notes PDF Download helpful for Class XII board examinations?

Revision notes for any subject are an extremely important study tool particularly for a subject like chemistry. Class XII Chemistry is an extensive subject that requires loads of cognizance and memorization. These revision notes can easily serve as a quick reference manual close to examinations. Students can study important points from them quickly. Revision notes for Chapter 2 "Electrochemistry" contain all important topics, which students need to refer to for Class XII Board exams.

5. Are Class 12 Chemistry Chapter 2 Notes available to download? If so, are they free?

Vedantu provides extremely useful notes for all the chapters of Class XII Chemistry. These notes can easily be downloaded at no cost from the Vedantu website or the Vedantu Mobile app. To download Class 12 Chemistry Chapter 2 Notes:


  • Visit the page Class 12 Chemistry Chapter 2 Notes.

  • You will be taken to the page containing the required revision notes.

  • As you scroll down you will find the option to "Download pdf." Click on it.

  • You will be redirected to a page containing the link to download the pdf of these revision notes.

6. Is Chapter 2 “Electrochemistry” a difficult chapter?

Class XII Chapter 2 "Electrochemistry" is a pretty important chapter for board exams.  Electrochemistry along with solutions, surface chemistry, and chemical kinetics carry a total weightage of 23 marks. The chapter carries important topics like Electrochemical cell, Galvanic cell, Electrolysis, etc. The chapter, if understood well, is not hugely difficult. Vedantu provides useful study material like NCERT Solutions, revision notes, question papers, and conceptual videos for this chapter.

7. What are some useful tips to ace the Class XII Chemistry Board exam?

Chemistry of Class XII may seem like an intimidating subject. But with some useful strategies, you can nail the CBSE board exams:

  • Pay attention during class. 

  • Be thorough with the NCERT textbook.

  • Make crisp and short notes.

  • Refer to NCERT Solutions, revision notes, sample papers, and previous years' question papers and practice well. Solve loads of question papers for practice. 

  • Revise extensively.

8. What are the important topics from Class 12 Electrochemistry Notes?

Electrochemistry is a pretty important chapter from the perspective of Class XII Board examinations. It contains significant topics like Electrochemical cells, Galvanic cells, Measurement of electrode potential, Nernst equation, The equilibrium constant from the Nernst equation, Electrochemical cells and Gibbs free energy of the reaction, The conductance of the electrolytic cells, Measurement of the conductivity of the ionic solution, Variation in conductivity and molar conductivity, and Kohlrausch's law and batteries. 

Students can refer to important questions on the page Important Questions for CBSE Class 12 Chemistry Chapter 2.

9. What is electrochemistry class 12 notes?

Electrochemistry Class 12 notes cover the fundamental concepts and principles related to the study of chemical reactions involving electricity and the transfer of electrons between substances.

10. What is an electrode in Class 12 Electrochemistry Notes?

Electrode Class 12 Electrochemistry Notes explain the role and function of electrodes in electrochemical cells, detailing their importance in facilitating electron transfer during redox reactions.

11. What is the most important topics of electrochemistry class 12?

The most important topics of electrochemistry Class 12 include oxidation-reduction reactions, galvanic cells, electrolytic cells, electrode potentials, and the Nernst equation.

12. What are the points to remember in class 12 Electrochemistry Notes PDF?

Points to remember in Class 12 Electrochemistry Notes PDF include understanding the difference between oxidation and reduction, grasping the concept of electrode potentials, recognizing the components of a galvanic cell and an electrolytic cell, and mastering the application of the Nernst equation in various scenarios.