Answer
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Hint: Centrifugal Force acts on every object moving in a circular path when viewed from a rotating frame of reference. The centrifugal force also depends on the mass of the object, the distance from the centre of the circle and also the speed of rotation. If the object has more mass, the force of the movement and the speed of the object will be greater. If the distance is far from the centre of the circle the force of the movement will be more.
Formula Used:
The mathematical formula for Centrifugal force is given as the negative product of mass (in kg) and tangential velocity (in meters per second) squared, divided by the radius (in meters). This implies that on doubling the tangential velocity, the centripetal force will be quadrupled. Mathematically it is written as:
\[{F_c} = \dfrac{{ - m{v^2}}}{r}\]
In this mathematical formula, $m$ is the mass of the object, $v$ is the velocity of the object and $r$ is the radius.
Complete step by step answer:
In this above numerical problem, the mass of the ball is given equal to $0.25kg$ and the force of tension is given equal to $25N$. Now, the radius of the string is given equal to $1.96m$.
Now, we can use the velocity as the subject of the formula and thus, the expression becomes:
${v^2} = \dfrac{{F \times r}}{m}$
Now, putting the values of force, radius and mass of the ball in the above expression, we get:
${v^2} = \dfrac{{25 \times 1.96}}{{0.25}} = 196$
Now to obtain the maximum velocity with which the ball rotates, we have to find the square root of the above value obtained. Thus, we get:
$v = 14m{s^{ - 1}}$
This is the maximum value with which the ball can rotate in the string before the string breaks.
Note: If an object is moving in a circle and experiences an outward force then this force is called the centrifugal force. The object has the direction along the centre of the circle from the centre approaching the object.
Formula Used:
The mathematical formula for Centrifugal force is given as the negative product of mass (in kg) and tangential velocity (in meters per second) squared, divided by the radius (in meters). This implies that on doubling the tangential velocity, the centripetal force will be quadrupled. Mathematically it is written as:
\[{F_c} = \dfrac{{ - m{v^2}}}{r}\]
In this mathematical formula, $m$ is the mass of the object, $v$ is the velocity of the object and $r$ is the radius.
Complete step by step answer:
In this above numerical problem, the mass of the ball is given equal to $0.25kg$ and the force of tension is given equal to $25N$. Now, the radius of the string is given equal to $1.96m$.
Now, we can use the velocity as the subject of the formula and thus, the expression becomes:
${v^2} = \dfrac{{F \times r}}{m}$
Now, putting the values of force, radius and mass of the ball in the above expression, we get:
${v^2} = \dfrac{{25 \times 1.96}}{{0.25}} = 196$
Now to obtain the maximum velocity with which the ball rotates, we have to find the square root of the above value obtained. Thus, we get:
$v = 14m{s^{ - 1}}$
This is the maximum value with which the ball can rotate in the string before the string breaks.
Note: If an object is moving in a circle and experiences an outward force then this force is called the centrifugal force. The object has the direction along the centre of the circle from the centre approaching the object.
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