
What is the basic cause of quantisation of charge?
Answer
134.1k+ views
Hint: If protons and electrons are the most fundamental particles and only charge carriers in the universe, then all the observable charges must be integral multiples of multiple electrons and protons.
Step by Step Answer
Charge quantization is the principle that the charge of an object is an integral multiple of the elementary charge.
Now, since protons and electrons are the only charge carriers in the universe, therefore all the observable charges must be integral multiple of electron. If an object contains $n$, electrons and ${n_2}$ protons, then the net charge on object is:
$ - {n_1}\left( e \right) + {n_2}\left( e \right) = \left( {{n_1} - {n_2}} \right)e$
Indeed, there are elementary particles other than protons and electrons, which carry charge. But all the elementary particles have charges which are integral multiple of $e$.. Thus charge on any object is always an integral multiple of $e$ and can be changed in steps of$e$, i.e. charge is quantized.
Note:
The step size $e$ is usually so small that we can easily neglect the quantization. If $l\,\mu \,C$ contains $n$ units of basic charge $e$ where,
$n = \dfrac{{l\,\mu \,C}}{{1.6 \times {{10}^{ - 19C}}}} = 6 \times {10^{12}}$
The step size is thus very small as compared to the charges usually found. Hence in many cases, we assume a continuous charge variation.
Step by Step Answer
Charge quantization is the principle that the charge of an object is an integral multiple of the elementary charge.
Now, since protons and electrons are the only charge carriers in the universe, therefore all the observable charges must be integral multiple of electron. If an object contains $n$, electrons and ${n_2}$ protons, then the net charge on object is:
$ - {n_1}\left( e \right) + {n_2}\left( e \right) = \left( {{n_1} - {n_2}} \right)e$
Indeed, there are elementary particles other than protons and electrons, which carry charge. But all the elementary particles have charges which are integral multiple of $e$.. Thus charge on any object is always an integral multiple of $e$ and can be changed in steps of$e$, i.e. charge is quantized.
Note:
The step size $e$ is usually so small that we can easily neglect the quantization. If $l\,\mu \,C$ contains $n$ units of basic charge $e$ where,
$n = \dfrac{{l\,\mu \,C}}{{1.6 \times {{10}^{ - 19C}}}} = 6 \times {10^{12}}$
The step size is thus very small as compared to the charges usually found. Hence in many cases, we assume a continuous charge variation.
Recently Updated Pages
JEE Main 2025 Session 2 Form Correction (Closed) – What Can Be Edited

What are examples of Chemical Properties class 10 chemistry JEE_Main

JEE Main 2025 Session 2 Schedule Released – Check Important Details Here!

JEE Main 2025 Session 2 Admit Card – Release Date & Direct Download Link

JEE Main 2025 Session 2 Registration (Closed) - Link, Last Date & Fees

JEE Mains Result 2025 NTA NIC – Check Your Score Now!

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Wheatstone Bridge for JEE Main Physics 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Diffraction of Light - Young’s Single Slit Experiment

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Elastic Collisions in One Dimension - JEE Important Topic

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main
