Why is the conversion of ethanol to ethanoic acid an oxidation reaction?
A. Carbon is oxidized
B. The hydrogen oxidation number is changed
C. Carbon is reduced
D. Carbon undergoes disproportionation
Answer
Verified
413k+ views
Hint: To answer this question you should first write the equation involved in the conversion of ethanol to ethanoic acid. Then, assign the oxidation number of each atom i.e. carbon and oxygen to answer the question correctly.
Complete step by step answer:
We can write the conversion of ethanol to ethanoic acid as:
$CH_{ 3 }CH_{ 2 }OH\quad +\quad KMnO_{ 4 }(Alkaline)\quad \rightarrow \quad CH_{ 3 }COOH$
If you can see the above change carefully you will notice that in this change one extra Oxygen (O) atom has been added and two Hydrogen (H) atoms are being removed from ethanol ($CH_{ 3 }CH_{ 2 }OH$) molecule to convert it into ethanoic acid ($CH_{ 3 }COOH$). The addition of Oxygen and removal of Hydrogen is known as oxidation.
Both these addition and removal are occurring on the same carbon. Hence, we can say that carbon is oxidized here.
Therefore, we conclude that the correct answer to this question is option A.
Additional information:
We should also know that the other most common oxidants are Jones reagent, PCC in DMF, Heyns oxidation and ruthenium tetroxide ($RuO_{ 4 }$)
Note: We should also know that, under controlled conditions, $KMnO_{ 4 }$ oxidizes alcohols to carboxylic acids efficiently. This reaction was first described in detail by Fournier, which is typically carried out by adding $KMnO_{ 4 }$ to a solution of the alcohol in an alkaline solution.
Complete step by step answer:
We can write the conversion of ethanol to ethanoic acid as:
$CH_{ 3 }CH_{ 2 }OH\quad +\quad KMnO_{ 4 }(Alkaline)\quad \rightarrow \quad CH_{ 3 }COOH$
If you can see the above change carefully you will notice that in this change one extra Oxygen (O) atom has been added and two Hydrogen (H) atoms are being removed from ethanol ($CH_{ 3 }CH_{ 2 }OH$) molecule to convert it into ethanoic acid ($CH_{ 3 }COOH$). The addition of Oxygen and removal of Hydrogen is known as oxidation.
Both these addition and removal are occurring on the same carbon. Hence, we can say that carbon is oxidized here.
Therefore, we conclude that the correct answer to this question is option A.
Additional information:
We should also know that the other most common oxidants are Jones reagent, PCC in DMF, Heyns oxidation and ruthenium tetroxide ($RuO_{ 4 }$)
Note: We should also know that, under controlled conditions, $KMnO_{ 4 }$ oxidizes alcohols to carboxylic acids efficiently. This reaction was first described in detail by Fournier, which is typically carried out by adding $KMnO_{ 4 }$ to a solution of the alcohol in an alkaline solution.
Recently Updated Pages
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Chemical Equation - Important Concepts and Tips for JEE
Concept of CP and CV of Gas - Important Concepts and Tips for JEE
Trending doubts
Physics Average Value and RMS Value JEE Main 2025
Inductive Effect and Acidic Strength - Types, Relation and Applications for JEE
Clemmenson and Wolff Kishner Reductions for JEE
The number of d p bonds present respectively in SO2 class 11 chemistry JEE_Main
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
JEE Main Physics Online Mock Test for Class 12
Other Pages
Revision Notes Class 11 Chemistry Chapter 7 - Redox Reactions
JEE Advanced 2025 Revision Notes for Practical Organic Chemistry
NCERT Solutions for Class 11 Chemistry In Hindi Chapter 7 Equilibrium
Collision - Important Concepts and Tips for JEE
Ideal and Non-Ideal Solutions Raoult's Law - JEE
Current Loop as Magnetic Dipole and Its Derivation for JEE