
In a certain particle accelerator, electrons emerge in pulses at the rate of 250 pulses per second. Each pulse is of duration of 200 ns and the electrons in the pulse constitute a current of 250 mA. The number of electrons delivered by the accelerator per pulse is
A) $8.00 \times {10^{10}}$
B) $5.00 \times {10^{10}}$
C) $3.13 \times {10^{10}}$
D) $9.60 \times {10^{10}}$
Answer
135k+ views
Hint:This question is from electricity. The problem is solved by the Electric Current concept. Apply the Electric Current equation to find the number of electrons delivered by the accelerator per pulse.
Formula used:
i) $I = \dfrac{q}{t}$
Where,
I = Current
q = Charge
t = time
ii) $n = \dfrac{q}{e}$
Where,
n = Number of electrons
q = Charge
e = Charge of an electron
Complete answer:
$I = \dfrac{q}{t}$
I = 25 mA = 0.25 A
t = 200 ns = $2 \times {10^{ - 7}}s$
The charge in a pulse will be,
$q = It$
$q = 0.25 \times 2 \times {10^{ - 7}} = 5 \times {10^{ - 8}}C$
The number of electrons delivered by the accelerator per pulse is given below.
$n = \dfrac{q}{e}$
$n = \dfrac{{5 \times {{10}^8}}}{{1.6 \times {{10}^{ - 19}}}} = 3.13 \times {10^{11}}$
Hence, the correct option is Option C) $3.13 \times {10^{10}}$.
Additional Information:
The electric current is a flow of charged particles (electrons) through wires and other components.
Electric current is the rate of flow of charge.
Electric current flows from the negative terminal of the cell to the positive terminal.
The conventional direction of electric current is taken as opposite to the direction of the flow of charge (electrons).
Note: The S.I unit of charge is coulomb and the S.I unit of electric current is ampere (coulomb per second).
Formula used:
i) $I = \dfrac{q}{t}$
Where,
I = Current
q = Charge
t = time
ii) $n = \dfrac{q}{e}$
Where,
n = Number of electrons
q = Charge
e = Charge of an electron
Complete answer:
$I = \dfrac{q}{t}$
I = 25 mA = 0.25 A
t = 200 ns = $2 \times {10^{ - 7}}s$
The charge in a pulse will be,
$q = It$
$q = 0.25 \times 2 \times {10^{ - 7}} = 5 \times {10^{ - 8}}C$
The number of electrons delivered by the accelerator per pulse is given below.
$n = \dfrac{q}{e}$
$n = \dfrac{{5 \times {{10}^8}}}{{1.6 \times {{10}^{ - 19}}}} = 3.13 \times {10^{11}}$
Hence, the correct option is Option C) $3.13 \times {10^{10}}$.
Additional Information:
The electric current is a flow of charged particles (electrons) through wires and other components.
Electric current is the rate of flow of charge.
Electric current flows from the negative terminal of the cell to the positive terminal.
The conventional direction of electric current is taken as opposite to the direction of the flow of charge (electrons).
Note: The S.I unit of charge is coulomb and the S.I unit of electric current is ampere (coulomb per second).
Recently Updated Pages
JEE Main 2025 Session 2 Form Correction (Closed) – What Can Be Edited

What are examples of Chemical Properties class 10 chemistry JEE_Main

JEE Main 2025 Session 2 Schedule Released – Check Important Details Here!

JEE Main 2025 Session 2 Admit Card – Release Date & Direct Download Link

JEE Main 2025 Session 2 Registration (Closed) - Link, Last Date & Fees

JEE Mains Result 2025 NTA NIC – Check Your Score Now!

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Elastic Collisions in One Dimension - JEE Important Topic

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Displacement-Time Graph and Velocity-Time Graph for JEE

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

JEE Advanced 2024 Syllabus Weightage

JEE Main Chemistry Question Paper with Answer Keys and Solutions
