
In step-up transformers the output voltage is $11\,KV$ and the input voltage is $220\,V$. The ratio of number of turns of secondary to primary is
$A)\,\,20:1 \\
B)\,\,22:1 \\
C)\,\,50:1 \\
D)\,\,1:50 \\ $
Answer
135.3k+ views
Hint: In the question the input voltage and output voltage of the step-up transformer is given. Substituting the known values in the equation of turns ratio we get the value of the number of turns of secondary to primary coils.
Formula used:
The expression for finding the number of turns in the coil is,
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{{{v_p}}}{{{v_s}}}$
Where ${i_p}$ be the number of turns in the primary coil, ${i_s}$be the number of turns in the secondary coil, ${v_p}$ be the potential of primary voltage and ${v_s}$ be the potential of secondary voltage.
Complete step by step solution:
Given that,
Potential of primary voltage ${v_p}\, = \,220\,V$
Potential of secondary voltage ${v_s}\, = \,11\,KV$
Convert the secondary voltage in terms of V, we get
Potential of secondary voltage ${v_s}\, = \,11000\,V$
Number of turns in the primary coil ${i_{p\,}}\, = \,?$
Number of turns in the secondary coil ${i_s}\, = \,?$
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{{{v_p}}}{{{v_s}}}...........\left( 1 \right)$
Substitute the known values in the equation $\left( 1 \right)$
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{{220}}{{11000}}$
Simplify the above equation we get
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{1}{{50}}$
Convert the above equation in terms of secondary to primary coils, we get
$\dfrac{{{i_s}}}{{{i_p}}} = \,\dfrac{{50}}{1}$
Therefore. the number of turns of the secondary to primary coils is $50:1$
Hence, from the above options, option C is correct.
Note: In the question, step up transformer is used. It states that the voltage increases the voltage by decreasing the current. In the question we need to find the number of turns in the secondary to primary coil. So reciprocal the values we get the value of secondary to primary coils. we know that the power is proportional to the voltage and current. In the question we use the equation called ratio of transformation. This is also a turns ratio.
Formula used:
The expression for finding the number of turns in the coil is,
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{{{v_p}}}{{{v_s}}}$
Where ${i_p}$ be the number of turns in the primary coil, ${i_s}$be the number of turns in the secondary coil, ${v_p}$ be the potential of primary voltage and ${v_s}$ be the potential of secondary voltage.
Complete step by step solution:
Given that,
Potential of primary voltage ${v_p}\, = \,220\,V$
Potential of secondary voltage ${v_s}\, = \,11\,KV$
Convert the secondary voltage in terms of V, we get
Potential of secondary voltage ${v_s}\, = \,11000\,V$
Number of turns in the primary coil ${i_{p\,}}\, = \,?$
Number of turns in the secondary coil ${i_s}\, = \,?$
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{{{v_p}}}{{{v_s}}}...........\left( 1 \right)$
Substitute the known values in the equation $\left( 1 \right)$
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{{220}}{{11000}}$
Simplify the above equation we get
$\dfrac{{{i_p}}}{{{i_s}}} = \,\dfrac{1}{{50}}$
Convert the above equation in terms of secondary to primary coils, we get
$\dfrac{{{i_s}}}{{{i_p}}} = \,\dfrac{{50}}{1}$
Therefore. the number of turns of the secondary to primary coils is $50:1$
Hence, from the above options, option C is correct.
Note: In the question, step up transformer is used. It states that the voltage increases the voltage by decreasing the current. In the question we need to find the number of turns in the secondary to primary coil. So reciprocal the values we get the value of secondary to primary coils. we know that the power is proportional to the voltage and current. In the question we use the equation called ratio of transformation. This is also a turns ratio.
Recently Updated Pages
JEE Main 2025 Session 2 Form Correction (Closed) – What Can Be Edited

What are examples of Chemical Properties class 10 chemistry JEE_Main

JEE Main 2025 Session 2 Schedule Released – Check Important Details Here!

JEE Main 2025 Session 2 Admit Card – Release Date & Direct Download Link

JEE Main 2025 Session 2 Registration (Closed) - Link, Last Date & Fees

JEE Mains Result 2025 NTA NIC – Check Your Score Now!

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Elastic Collisions in One Dimension - JEE Important Topic

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Displacement-Time Graph and Velocity-Time Graph for JEE

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

JEE Advanced 2024 Syllabus Weightage

JEE Main Chemistry Question Paper with Answer Keys and Solutions
