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Hint: First calculate the work done by the camel on the load during the accelerated motion by using the kinetic energy and similarly the work done by the camel on the load during the retarded motion.
Complete step by step solution:
In this question, we have given the load is $1000kg$ and friction coefficient ${\mu _k} = 0.1$ and ${\mu _s} = 0.2$.
Mass of the camel is $500kg$.
Hence, Work done by camel on load during the accelerated motion is, $\left( {\dfrac{1}{2}m{v^2} - 0} \right) - \left( { - {u_k}mgr} \right)$
[$r$ is retardation]
Now we will substitute the values in the above equation as,
$\therefore \dfrac{1}{2} \times 1000 \times {5^2} + \left( {0.1 \times 1000 \times 10 \times 50} \right) = 62500$
Now work done by the came on load during the retarded motion is, $\left( {0 - \dfrac{1}{2}m{v^2}} \right) - \left( { - {u_k}mgr} \right)$\[\]$ = \left( {0.1 \times 1000 \times 10 \times 50} \right) - \dfrac{1}{2} \times 1000 \times {5^2} = 37500$
Hence the ratio will be $ \Rightarrow \dfrac{{62500}}{{37500}} = 5:3$.
Additional information:
If a body falls from rest, it is moving twice as fast after two seconds as it was moving after one second and moving three times faster after three seconds as it was after one second. A uniformly accelerated motion is the one in which the acceleration of the particle is uniform throughout the motion. Projectile motion is the perfect example of an accelerated motion. This acceleration is worked on the particle due to the gravity of the particle. Let a car is moving with some velocity and now the driver apply the break so there is change in velocity and the acceleration is negative and the motion of the car is said to be retarded.
Note: As we know that acceleration is a vector quantity that has magnitude and direction. Here acceleration is taken as negative because the direction of acceleration is opposite to the direction of gravity.
Complete step by step solution:
In this question, we have given the load is $1000kg$ and friction coefficient ${\mu _k} = 0.1$ and ${\mu _s} = 0.2$.
Mass of the camel is $500kg$.
Hence, Work done by camel on load during the accelerated motion is, $\left( {\dfrac{1}{2}m{v^2} - 0} \right) - \left( { - {u_k}mgr} \right)$
[$r$ is retardation]
Now we will substitute the values in the above equation as,
$\therefore \dfrac{1}{2} \times 1000 \times {5^2} + \left( {0.1 \times 1000 \times 10 \times 50} \right) = 62500$
Now work done by the came on load during the retarded motion is, $\left( {0 - \dfrac{1}{2}m{v^2}} \right) - \left( { - {u_k}mgr} \right)$\[\]$ = \left( {0.1 \times 1000 \times 10 \times 50} \right) - \dfrac{1}{2} \times 1000 \times {5^2} = 37500$
Hence the ratio will be $ \Rightarrow \dfrac{{62500}}{{37500}} = 5:3$.
Additional information:
If a body falls from rest, it is moving twice as fast after two seconds as it was moving after one second and moving three times faster after three seconds as it was after one second. A uniformly accelerated motion is the one in which the acceleration of the particle is uniform throughout the motion. Projectile motion is the perfect example of an accelerated motion. This acceleration is worked on the particle due to the gravity of the particle. Let a car is moving with some velocity and now the driver apply the break so there is change in velocity and the acceleration is negative and the motion of the car is said to be retarded.
Note: As we know that acceleration is a vector quantity that has magnitude and direction. Here acceleration is taken as negative because the direction of acceleration is opposite to the direction of gravity.
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