The threshold wavelength for photoelectric emission from a material is $5,200{{A}^{0}}$,
Photo electrons will be emitted when this material is illuminated with monochromatic radiation from a:
(A) 50-watt infrared lamp
(B) 1-watt infrared lamp
(C) 1 watt ultraviolet lamp
(D) 50-watt sodium vapour lamp
Answer
Verified
120.9k+ views
Hint: We know that the threshold wavelength is defined as the maximum wavelength that the incident radiation must have so that the photoelectric effect takes place. We should also know that the frequency of the incident light is less than the threshold frequency. No photoelectrons will be emitted from the metal surface. Based on this concept we have to answer this question.
Complete step by step answer:
At first let us mention the values of the questions that are mentioned to us:
Threshold wavelength =$5,200{{A}^{0}}$which can also be written as 520nm
We know that the formula of energy is given as: $\dfrac{he}{\lambda }$
In the above expression;
h is the Planck constant; e is the charge of the electron and $\lambda$is the wavelength.
So, now we have evaluated to get the value as:
$=\dfrac{1240}{520}eV\ \left( he=1240eV-nm \right)$
$=2.38eV$
So, the threshold energy is $=2.38eV$
So, for ejection of electrons energy of incident rays should be more than $2.38eV$.
Hence, the correct answer is Option C.
Note: We know that electromagnetic radiation, especially visible radiation of only one frequency or wavelength. Completely monochromatic radiation cannot be produced, but lasers produce radiation within a very narrow frequency band.
It should also be known to us that the term monochromatic originally means having only one single colour. Different optical wavelengths of the visible light are associated with the different perceived colours. However, light colours are rarely a criterion for monochromatically in the practice, and the non-monochromatic light can also have specific colours.
Complete step by step answer:
At first let us mention the values of the questions that are mentioned to us:
Threshold wavelength =$5,200{{A}^{0}}$which can also be written as 520nm
We know that the formula of energy is given as: $\dfrac{he}{\lambda }$
In the above expression;
h is the Planck constant; e is the charge of the electron and $\lambda$is the wavelength.
So, now we have evaluated to get the value as:
$=\dfrac{1240}{520}eV\ \left( he=1240eV-nm \right)$
$=2.38eV$
So, the threshold energy is $=2.38eV$
So, for ejection of electrons energy of incident rays should be more than $2.38eV$.
Hence, the correct answer is Option C.
Note: We know that electromagnetic radiation, especially visible radiation of only one frequency or wavelength. Completely monochromatic radiation cannot be produced, but lasers produce radiation within a very narrow frequency band.
It should also be known to us that the term monochromatic originally means having only one single colour. Different optical wavelengths of the visible light are associated with the different perceived colours. However, light colours are rarely a criterion for monochromatically in the practice, and the non-monochromatic light can also have specific colours.
Recently Updated Pages
What is Hybridisation? Types, Examples, and Importance
Young's Double Slit Experiment Step by Step Derivation
Difference Between Circuit Switching and Packet Switching
Difference Between Mass and Weight
JEE Main Participating Colleges 2024 - A Complete List of Top Colleges
JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips
Trending doubts
JEE Mains 2025: Check Important Dates, Syllabus, Exam Pattern, Fee and Updates
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Chemistry Question Paper with Answer Keys and Solutions
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions
JEE Main Chemistry Exam Pattern 2025
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
Dual Nature of Radiation and Matter Class 12 Notes CBSE Physics Chapter 11 (Free PDF Download)
Electric field due to uniformly charged sphere class 12 physics JEE_Main