Answer
Verified
447.9k+ views
Hint: To solve this question one should have knowledge of shapes and also remember that Inner curved surface area =$2\pi rl$, where r is inner radius and curved surface area =$2\pi Rl$, where R is the outer radius.
Complete step-by-step solution
And total surface area of a hollow cylindrical pipe =$2\pi (R + r)(R - r + h)$, where h is the height or length of the pipe.
According to question, length of cylindrical pipe = 77cm
Since, Inner diameter = 4cm
Therefore, Inner radius = $\dfrac{4}{2} = 2cm$
Also, Outer diameter is given = 4.4cm
So, Outer radius = $\dfrac{{4.4cm}}{2} = 2.2cm$
We know that formula of Inner curved surface area = $2\pi rl$ here r is the inner radius and l is the length of the metal pipe
So, substituting the values in the above formula, we get
Inner curved surface area = $2 \times \dfrac{{22}}{7} \times 2 \times 77 = 968c{m^2}$
Also, we know that formula of Outer curved surface area = $2\pi Rl$ here R is the outer radius and l is the length of the metal pipe
Now substituting the values in the above formula, we get
Outer curved surface area = $2 \times \dfrac{{22}}{7} \times 2.2 \times 77 = 1064.8c{m^2}$
So, to find the Total surface area which is equal to inner surface area of metal pipe + outer surface area of metal pipe + surface area of both bases
And we know that surface area of base can be found as; area of outer circle – area of inner circle
And we know that area of circle is equal to $\pi {r^2}$here r is the radius
Therefore, surface area of base = \[\pi {R^2} - \pi {r^2}\]
So, Total surface area = $2\pi (R + r)(R - r + h)$
Now substituting the values in the above formula, we get
Total surface area = $2 \times \dfrac{{22}}{7}(2.2 + 2)(2.2 - 2 + 77)c{m^2}$= $\dfrac{{44}}{7} \times 4.2 \times 77.2c{m^2} = 2038.08c{m^2}$
(i). Hence, Inner curved surface area = $968c{m^2}$
(ii). Outer curved surface area = $1064.8c{m^2}$
(iii). And, total surface area = $2038.08c{m^2}$
Note: Total surface area can also be calculated by adding inner curved surface area, outer curved surface, and twice the area of the concentric circle which was formed by outer radius and inner radius. Area of concentric circle =$\pi {R^2} - \pi {r^2}$, where R = radius of outer circle and r = radius of inner circle.
Complete step-by-step solution
And total surface area of a hollow cylindrical pipe =$2\pi (R + r)(R - r + h)$, where h is the height or length of the pipe.
According to question, length of cylindrical pipe = 77cm
Since, Inner diameter = 4cm
Therefore, Inner radius = $\dfrac{4}{2} = 2cm$
Also, Outer diameter is given = 4.4cm
So, Outer radius = $\dfrac{{4.4cm}}{2} = 2.2cm$
We know that formula of Inner curved surface area = $2\pi rl$ here r is the inner radius and l is the length of the metal pipe
So, substituting the values in the above formula, we get
Inner curved surface area = $2 \times \dfrac{{22}}{7} \times 2 \times 77 = 968c{m^2}$
Also, we know that formula of Outer curved surface area = $2\pi Rl$ here R is the outer radius and l is the length of the metal pipe
Now substituting the values in the above formula, we get
Outer curved surface area = $2 \times \dfrac{{22}}{7} \times 2.2 \times 77 = 1064.8c{m^2}$
So, to find the Total surface area which is equal to inner surface area of metal pipe + outer surface area of metal pipe + surface area of both bases
And we know that surface area of base can be found as; area of outer circle – area of inner circle
And we know that area of circle is equal to $\pi {r^2}$here r is the radius
Therefore, surface area of base = \[\pi {R^2} - \pi {r^2}\]
So, Total surface area = $2\pi (R + r)(R - r + h)$
Now substituting the values in the above formula, we get
Total surface area = $2 \times \dfrac{{22}}{7}(2.2 + 2)(2.2 - 2 + 77)c{m^2}$= $\dfrac{{44}}{7} \times 4.2 \times 77.2c{m^2} = 2038.08c{m^2}$
(i). Hence, Inner curved surface area = $968c{m^2}$
(ii). Outer curved surface area = $1064.8c{m^2}$
(iii). And, total surface area = $2038.08c{m^2}$
Note: Total surface area can also be calculated by adding inner curved surface area, outer curved surface, and twice the area of the concentric circle which was formed by outer radius and inner radius. Area of concentric circle =$\pi {R^2} - \pi {r^2}$, where R = radius of outer circle and r = radius of inner circle.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Find the value of the expression given below sin 30circ class 11 maths CBSE
In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Why is there a time difference of about 5 hours between class 10 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE