Answer
Verified
455.4k+ views
Hint: The sugars can be written using Haworth's formula. Pyranose and Furanose are the oxides rings that resemble the oxygen-containing heterocyclic ring pyran and furan respectively. These are five or six-membered rings where one of the positions is occupied by oxide. The Furanose structure is similar to the 5-membered heterocyclic ring furan.
Complete step by step solution:
Fructose occurs in fruits and it is called the fruit sugar. It is also present in honey and sweet fruits along with glucose. In the combined state, it is also present in disaccharide and polysaccharide (insulin).
Its molecular formula is $\text{ }{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{12}}}{{\text{O}}_{\text{6}}}$. It contains the keto group at C-2 and the six carbon atoms are arranged in a straight chain. The Fischer projection of the fructose can be converted into the cyclic structure.
Like glucose, fructose has a cyclic structure. The hemiacetal is formed by the intramolecular combination of ${{\text{C}}_{\text{2}}}$ , keto group and $-\text{OH}$ a group of ${{\text{C}}_{6}}$ the atom. As a result, ${{\text{C}}_{\text{2}}}$ the atom becomes asymmetric and therefore D-fructose has two possible isomers as a $\text{ }\!\!\alpha\!\!\text{ -D-fructose}$ and $\text{ }\!\!\beta\!\!\text{ -D-fructose}$.
These structures were suggested by Haworth and are known as the Haworth projection formulae or pyranose structures.
The $\text{ }\!\!\beta\!\!\text{ -D-fructose}$ structure is as follows:
To write the pyranose structures for any monosaccharide first, draw a pentagon with its oxygen atom at the top. The terminal $\text{-C}{{\text{H}}_{\text{2}}}\text{OH}$ group as shown in the figure is always placed above the plane of the pentagon ring. Place all the groups which are present on the left-hand side in Fischer projection above the plane of the ring and all those groups on the right hand in Fischer projection below the plane of the ring.
Pyranose rings are formed by the reaction of the keto group on the carbon number two of sugar with the hydroxyl which is at the carbon one. This formation goes through the hemiacetal. This structure is similar to the furan ring. The hemiacetal structure is as shown below:
Thus here we know that the five-membered rings of oxide are called the pyranose. Due to the formation of an oxide ring, the new asymmetric carbon atom is created at the carbonyl carbon, which is called an anomeric carbon atom.
Two different configurations are possible at the anomeric carbon atom and they are called the anomers.
Here, the two structures shown above are all similar except at the C-2 carbon atom. In $\text{ }\!\!\alpha\!\!\text{ -D-fructose}$ the hydroxyl ion below the plane and $\text{ }\!\!\beta\!\!\text{ -D-fructose}$ the hydroxyl ion is above the plane.
Note: Remember that groups which are on the right in a Fischer projection are written down in Haworth projection and groups which are on the left in a Fischer projection are up in a Haworth projection. The fructose belongs to the D-series and is a laevorotatory compound. It is also called laevulose.
Complete step by step solution:
Fructose occurs in fruits and it is called the fruit sugar. It is also present in honey and sweet fruits along with glucose. In the combined state, it is also present in disaccharide and polysaccharide (insulin).
Its molecular formula is $\text{ }{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{12}}}{{\text{O}}_{\text{6}}}$. It contains the keto group at C-2 and the six carbon atoms are arranged in a straight chain. The Fischer projection of the fructose can be converted into the cyclic structure.
Like glucose, fructose has a cyclic structure. The hemiacetal is formed by the intramolecular combination of ${{\text{C}}_{\text{2}}}$ , keto group and $-\text{OH}$ a group of ${{\text{C}}_{6}}$ the atom. As a result, ${{\text{C}}_{\text{2}}}$ the atom becomes asymmetric and therefore D-fructose has two possible isomers as a $\text{ }\!\!\alpha\!\!\text{ -D-fructose}$ and $\text{ }\!\!\beta\!\!\text{ -D-fructose}$.
These structures were suggested by Haworth and are known as the Haworth projection formulae or pyranose structures.
The $\text{ }\!\!\beta\!\!\text{ -D-fructose}$ structure is as follows:
To write the pyranose structures for any monosaccharide first, draw a pentagon with its oxygen atom at the top. The terminal $\text{-C}{{\text{H}}_{\text{2}}}\text{OH}$ group as shown in the figure is always placed above the plane of the pentagon ring. Place all the groups which are present on the left-hand side in Fischer projection above the plane of the ring and all those groups on the right hand in Fischer projection below the plane of the ring.
Pyranose rings are formed by the reaction of the keto group on the carbon number two of sugar with the hydroxyl which is at the carbon one. This formation goes through the hemiacetal. This structure is similar to the furan ring. The hemiacetal structure is as shown below:
Thus here we know that the five-membered rings of oxide are called the pyranose. Due to the formation of an oxide ring, the new asymmetric carbon atom is created at the carbonyl carbon, which is called an anomeric carbon atom.
Two different configurations are possible at the anomeric carbon atom and they are called the anomers.
Here, the two structures shown above are all similar except at the C-2 carbon atom. In $\text{ }\!\!\alpha\!\!\text{ -D-fructose}$ the hydroxyl ion below the plane and $\text{ }\!\!\beta\!\!\text{ -D-fructose}$ the hydroxyl ion is above the plane.
Note: Remember that groups which are on the right in a Fischer projection are written down in Haworth projection and groups which are on the left in a Fischer projection are up in a Haworth projection. The fructose belongs to the D-series and is a laevorotatory compound. It is also called laevulose.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Give 10 examples for herbs , shrubs , climbers , creepers
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE