Answer
Verified
445.5k+ views
Hint: The law of Ampere is a mathematical assertion of the relation between currents and their induced magnetic fields. The law of Ampere helps one to cross the distance between electricity and magnetism, that is, it gives us a quantitative relationship between electric currents and magnetic fields.
Complete step by step answer:
Ampere’s circuital law states that the magnetic field integral of the closed line around a current bearing conductor is proportional to absolute permeability times the overall passing current of the conductor.
Mathematically it is given by-
$\oint {\overrightarrow I } .\overrightarrow {dl} = {\mu _ \circ }{I_{enclosed}}$ , where ${\mu _ \circ } = $ permeability of free space, $dl = $ small parts of length
To know the Ampere’s circuital law let us take a steady current carrying wire of uniform cross-section.
Now we have to calculate the magnetic field inside the region ( $r < a$ ) in the wire where current is uniformly distributed and the wire has a circular cross-section. The current is steady current.
Now let us consider the given figure-
In this figure, magnetic field lines form concentric circles centred on O. The axis of the cylindrical string.
Hence, it is the preferred part of the loop. Here there are two concentric circles. The radius of the large circle is $a$
and the radius of the smaller circle is $r$.
Now consider a loop of radius $a < r$
The cross-sectional area ( $\pi {a^2}$) current is $I$
Then, the enclosed current for area $\pi {r^2}$ is ${I_{enclosed}} = \dfrac{{{r^2}}} {{{a^2}}}I$
Taking the integral magnetic field around the coil, we get-
$\oint {\overrightarrow B } .\overrightarrow {dl} = B \times 2\pi r$
Using Ampere’s circuital law, we get-
$ B \times 2\pi r = \dfrac{{{\mu _ \circ }I{r^2}}}{{{a^2}}} \\
B = \dfrac{{{\mu _ \circ }rI}}
{{2\pi {a^2}}} \\ $
Note:
While calculating the magnetic field using Ampere’s circuital law we have to see that the current flowing in the conductor is steady current. Otherwise the law will not be valid. Also the direction of the magnetic field can be found using Fleming’s left hand rule.
Complete step by step answer:
Ampere’s circuital law states that the magnetic field integral of the closed line around a current bearing conductor is proportional to absolute permeability times the overall passing current of the conductor.
Mathematically it is given by-
$\oint {\overrightarrow I } .\overrightarrow {dl} = {\mu _ \circ }{I_{enclosed}}$ , where ${\mu _ \circ } = $ permeability of free space, $dl = $ small parts of length
To know the Ampere’s circuital law let us take a steady current carrying wire of uniform cross-section.
Now we have to calculate the magnetic field inside the region ( $r < a$ ) in the wire where current is uniformly distributed and the wire has a circular cross-section. The current is steady current.
Now let us consider the given figure-
In this figure, magnetic field lines form concentric circles centred on O. The axis of the cylindrical string.
Hence, it is the preferred part of the loop. Here there are two concentric circles. The radius of the large circle is $a$
and the radius of the smaller circle is $r$.
Now consider a loop of radius $a < r$
The cross-sectional area ( $\pi {a^2}$) current is $I$
Then, the enclosed current for area $\pi {r^2}$ is ${I_{enclosed}} = \dfrac{{{r^2}}} {{{a^2}}}I$
Taking the integral magnetic field around the coil, we get-
$\oint {\overrightarrow B } .\overrightarrow {dl} = B \times 2\pi r$
Using Ampere’s circuital law, we get-
$ B \times 2\pi r = \dfrac{{{\mu _ \circ }I{r^2}}}{{{a^2}}} \\
B = \dfrac{{{\mu _ \circ }rI}}
{{2\pi {a^2}}} \\ $
Note:
While calculating the magnetic field using Ampere’s circuital law we have to see that the current flowing in the conductor is steady current. Otherwise the law will not be valid. Also the direction of the magnetic field can be found using Fleming’s left hand rule.
Recently Updated Pages
Consider the polynomial fleft x right 1 + 2x + 3x2 class 12 maths CBSE
Consider the following statements Statement I The area class 12 maths CBSE
Consider the following linear programming problem Maximize class 12 maths CBSE
Consider the following four statements ad and select class 12 biology CBSE
Consider the following compounds Hyperconjugation occurs class 12 chemistry CBSE
Consider the charges q q and q placed at the vertices class 12 physics CBSE
Trending doubts
Which are the Top 10 Largest Countries of the World?
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Explain sex determination in humans with the help of class 12 biology CBSE
How much time does it take to bleed after eating p class 12 biology CBSE
Distinguish between asexual and sexual reproduction class 12 biology CBSE
Differentiate between insitu conservation and exsitu class 12 biology CBSE