How do you simplify \[(x-4)({{x}^{2}}+3x+2)\]?
Answer
Verified
433.2k+ views
Hint: We are given an expression consisting of a product of a monomial and a quadratic equation which we have to simplify. We will open the brackets and multiply each term of the monomial with the quadratic equation. Upon solving the resultant terms, we will get the simplified form of the given expression.
Complete step by step answer:
According to the given question, we have to simplify the given expression. We will begin by writing the given expression, we have,
\[(x-4)({{x}^{2}}+3x+2)\]----(1)
We will multiply each terms of the monomial with the bracket of the quadratic equation and we will get it as,
So we will multiply \[x\] and \[-4\] with \[({{x}^{2}}+3x+2)\]. We will get
\[\Rightarrow x({{x}^{2}}+3x+2)-4({{x}^{2}}+3x+2)\]
So, \[x\] will multiply with \[{{x}^{2}}\] to give \[{{x}^{3}}\], \[x\] will multiply with \[3x\] to give \[3{{x}^{2}}\] and with \[2\] to give \[2x\]. Similarly, \[-4\] will multiply with \[{{x}^{2}}\] to give \[-4{{x}^{2}}\], \[-4\] will multiply with \[3x\] to give \[-12x\] and \[-4\] will multiply with \[2\] to give \[-8\].
Multiplying the corresponding terms, we will get,
\[\Rightarrow {{x}^{3}}+3{{x}^{2}}+2x-4{{x}^{2}}-12x-8\]
Now, we will arrange the above expression in terms of the decreasing powers of the terms.
We get,
\[\Rightarrow {{x}^{3}}+3{{x}^{2}}-4{{x}^{2}}+2x-12x-8\]
We can see that for the coefficients of \[{{x}^{2}}\], we have the terms as \[3{{x}^{2}}\] and \[-4{{x}^{2}}\], adding them we get it as \[-{{x}^{2}}\].
Similarly, for the coefficients of \[x\], we have the terms as \[2x\] and \[-12x\], adding the terms we get \[-10x\].
Solving further we get the new simplified expression as,
\[\Rightarrow {{x}^{3}}-{{x}^{2}}-10x-8\]
Therefore, the simplified expression is \[{{x}^{3}}-{{x}^{2}}-10x-8\].
Note: In the above solution, we multiplied the monomial terms with the quadratic equation but we can also do it the other way round, that is, we can multiply the terms of the quadratic equation with the monomial equation and we will still get the same simplified answer. While multiplying the numbers, write the resulting values correctly.
Complete step by step answer:
According to the given question, we have to simplify the given expression. We will begin by writing the given expression, we have,
\[(x-4)({{x}^{2}}+3x+2)\]----(1)
We will multiply each terms of the monomial with the bracket of the quadratic equation and we will get it as,
So we will multiply \[x\] and \[-4\] with \[({{x}^{2}}+3x+2)\]. We will get
\[\Rightarrow x({{x}^{2}}+3x+2)-4({{x}^{2}}+3x+2)\]
So, \[x\] will multiply with \[{{x}^{2}}\] to give \[{{x}^{3}}\], \[x\] will multiply with \[3x\] to give \[3{{x}^{2}}\] and with \[2\] to give \[2x\]. Similarly, \[-4\] will multiply with \[{{x}^{2}}\] to give \[-4{{x}^{2}}\], \[-4\] will multiply with \[3x\] to give \[-12x\] and \[-4\] will multiply with \[2\] to give \[-8\].
Multiplying the corresponding terms, we will get,
\[\Rightarrow {{x}^{3}}+3{{x}^{2}}+2x-4{{x}^{2}}-12x-8\]
Now, we will arrange the above expression in terms of the decreasing powers of the terms.
We get,
\[\Rightarrow {{x}^{3}}+3{{x}^{2}}-4{{x}^{2}}+2x-12x-8\]
We can see that for the coefficients of \[{{x}^{2}}\], we have the terms as \[3{{x}^{2}}\] and \[-4{{x}^{2}}\], adding them we get it as \[-{{x}^{2}}\].
Similarly, for the coefficients of \[x\], we have the terms as \[2x\] and \[-12x\], adding the terms we get \[-10x\].
Solving further we get the new simplified expression as,
\[\Rightarrow {{x}^{3}}-{{x}^{2}}-10x-8\]
Therefore, the simplified expression is \[{{x}^{3}}-{{x}^{2}}-10x-8\].
Note: In the above solution, we multiplied the monomial terms with the quadratic equation but we can also do it the other way round, that is, we can multiply the terms of the quadratic equation with the monomial equation and we will still get the same simplified answer. While multiplying the numbers, write the resulting values correctly.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
Find the value of x if the mode of the following data class 11 maths CBSE
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Difference Between Plant Cell and Animal Cell
What is pollution? How many types of pollution? Define it
What is the color of ferrous sulphate crystals? How does this color change after heating? Name the products formed on strongly heating ferrous sulphate crystals. What type of chemical reaction occurs in this type of change.