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Parallelogram Law of Vectors

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To Find the Weight of a Given Body Using Parallelogram Law of Vectors

This law can be explained as, “If two forces acting simultaneously on a particle are represented in magnitude and direction by the two adjacent sides of the parallelogram, the diagonal of that parallelogram will be expressed as the resultant of these two forces represented in direction and magnitude.”


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Aim

The main objective of this experiment is to find the weight of the given object (body) applying the law of forces.


This is the basic law followed by basic mechanics. Its applications are used as lifting loads of cranes and bracket stay wires, etc.


Apparatus

To conduct this experiment, we need some essential apparatus such as;


  • Gravesand's apparatus which is an ideal apparatus for parallelogram law of forces

  • An object with an unknown weight (used for identifying its weight)

  • Plumb line

  • Slotted weights are hung with two hangers

  • The thread which is thin as well as durable

  • White colour drawing sheet

  • Pins to hook up drawing sheet

  • Pointed pencil (2HB)

  • Mirror strip

  • Set squares

  • Half-meter scale

  • Protractor


To Find the Weight of a Given Body Using Parallelogram

It can be calculated by the use of Gravesand's apparatus. The concept is that the vector sum of the forces experienced by the two masses hanging on the pulley is equal to the force of the object hanging in the middle. The same force is experienced by the mass in the middle.


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If an anonymous weight body (S) is suspended from the centre of the hanger, and P and Q are the two symmetric weights from the other end of the hanger, then that unknown weight can be calculated by using the equation below;


\[S=\sqrt{P^2+Q^2+2PQcos\theta }\]


Where,


\[\vec{P},\vec{Q}\] are two identical forces


The unknown weight can be termed S


P and Q are the balance weights used in the experiment


θ is the angle between two forces


Procedure

To Find the Weight of a Given Body Using Parallelogram Law of Vector. We need to follow certain steps to do so:


Gravesand's apparatus is set up with a board vertically with the help of a plumb line.


P1 and P2 pulleys should be oiled properly to make them frictionless


Fix the white sheet on the board with the help of drawing pins.


“O” is the knot shaped 


P and Q are the weights that are tied up at both the ends of the hanger and S be the third body tied at the third end.


Junction O should be sustained at equilibrium by maintaining weights P and Q.


P, Q, and S these three weights act as three forces \[\vec{P},\vec{Q}\]and\[\vec{S}\]


These weights should be hung freely without making any contact with the board.


Mark the position of the junction of O with the help of a dark pencil.


Disturb the weights at P and Q and leave them free.

The position of junction O will be closed as compared to the earlier position.


Let the position of P be P1 and P2, Q1 and Q2 will be the position of Q and S1 and S2 will be the position of S. All these positions are being written down with the use of a mirror.


By taking a scale, 1cm =50gm


OA = 3cm and


OB= 3cm


These parameters are taken to represent 


P = 150 gm and Q = 150 gm


Where R is represented by finishing the parallelogram OACB and by drawing OC line with the use of set squares


When measuring OC, the result shows 3.9cm.


P and Q can be altered for different sets.


By utilizing spring balance, calculate the weight of the wooden box.


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(Image will be Uploaded Soon)


To Find the Weight of a Given Body Using Parallelogram Law of Vectors Observation Table

Least count of spring balance = …… g


Zero error of spring balance = …….. G


Weight of unknown body by spring balance = …….g


Scale used: Let 1 cm = 50 g


Serial No.

Forces

Slides

R(Resultant force) in gram 

Unknown weight S in grams

Weight by spring balance in grams

Error Weight in grams


(grams)

Q

(grams)

OA

(cm)

OB

(cm)

OC

(cm)


1.

150

150

3

3

3.9

195

195

200

5


Calculations

After all the measurements


OC = 3.9cm, R = 50 * 3.9 = 195 g


Unknown weight is calculated as, S =195 g


Mean unknown weight will be S = \[\frac{(S_1+S_2+S_3)}{3}\] = 195 g


Weight measured from spring balance = 200 g


So the error is calculated through the difference between weight measured and mean unknown weight such as;


200g-195g = 5g


The error in this experiment is under its limits as per experimental error.


Results

The unknown weight of the given body = 195g


The error is within the limits of experimental error.


Learn about Precautions

  • The board used for the experiment should be placed vertically and stable.

  • Try to make these pulleys friction-free.

  • The table and board should not make any contact with the hangers.

  • The junction O should lie in the middle of the paper

  • The points should be marked when weights are stationary.

  • A sharp pencil (2HB) should be useful to mark all the points.

  • Arrows should be indicated to show the direction of forces.

  • A proper scale should be used for making a fairly big parallelogram.


To Evaluate Sources of Error

  • Friction in the pulleys might cause an error.

  • The accuracy of weights might vary.

  • The marked point may be correct.

  • The accuracy of weight obtained from spring balance may not be accurate.


Learning Outcomes

  • Students learn exactly what the parallelogram law of vectors is.

  • Gravesand's apparatus is familiarized with them.

  • Using the parallelogram law of vectors, students can find the unknown weight of an object.

FAQs on Parallelogram Law of Vectors

1. What is the Definition of the Parallelogram Law of Vector Addition?

If two vectors act simultaneously to represent the magnitude and direction as the two sides of a parallelogram, then the diagonal is depicted as the resultant of these two vectors. 

2. What is the Rule of the Parallelogram?

The easiest form of parallelogram law (also called parallelogram identity) belongs to geometry in mathematics. It states that the summation of squares of the lengths of the four sides of a parallelogram equals the sum of the squares of the lengths of the two diagonals.

3. What are the Examples of the Parallelogram?

A parallelogram consists of four sides, and these sides opposite each other are parallel, i.e. they don’t intersect. Some examples are squares, rhombuses, and rectangles.

4. How to Calculate the Mean Unknown Weight in Gravesand’s Apparatus?

Suppose we are getting three unknown weights such as:


S1 = 195g; S2 = 195.5g; S3 = 194.5g 


The unknown mean weight will be, 


S = (S1+S2+S3)/3 = (195+195.5+194.5)/3 = 195g

5. Define the addition of vectors?

The operation of adding two or more vectors together to form a vector sum is known as the addition of vectors.

6. Why is the addition of vectors different from the addition of scalars?

The addition of a vector has both direction and magnitude, whereas adding a scalar only has magnitude. As a result, adding a vector is not the same as adding a scalar.

7. How a vector is multiplied by a number?

The magnitude of a vector changes when it is multiplied by a positive number, but the direction remains the same. When a vector is multiplied by a negative number, not only does its magnitude change but also its direction is reversed.

8. Define the following: (a) unit vector (b) null vector (c) position vector (d) negative vector

  • The magnitude of a unit vector is unity '1', and it just denotes the direction.

  • A null vector is one whose magnitude is zero and which can have any arbitrary direction or none at all. It's also known as a zero vector.

  • A position vector is a vector that specifies a point's position concerning the origin of reference axes.

  • The negative of a vector is the vector that is equal in magnitude but moves in the opposite direction of that vector.

9.What are scalar and vector quantities?

  • A scalar is a physical quantity that has no direction and is completely represented only by magnitude with a suitable unit, e.g. time, mass, speed, density, work, energy, and so on.

  • A vector is a physical quantity that has both "magnitude and a specified direction," for example, displacement, velocity, acceleration, force, weight, torque, momentum, magnetic field intensity, and electric field intensity.

10.What are the main sources of error in the experiment using Gravesand’s apparatus?

 Its sources of error are:

  • Friction in the pulleys.

  • Weights in the threads

11.What is the importance of practicals?

One of the most important subjects is physics. As the CBSE exam approaches, students become busy studying various subjects. However, the practical exams, which are of 30 marks, are a significant part of the CBSE exam.


To understand all the topics of 12th-grade physics in detail, students must know all the experiments as well as theorems, laws, and numerical. In the practical exam, two experiments (8 + 8 marks) are required from each section. Six marks are awarded for experiment records and activities, three marks are given for the project, and viva on the experiment consists of 5 marks.


The Physics practicals For Class 12 CBSE are provided here so that students can better understand the experiments. Before experimenting, students should study the theory and law behind it. Also, go through the viva voce questions and answers for each experiment that are available on the website.

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